Thermal Properties Of Matter Ques 36
36. If $1$ $ g$ of steam is mixed with $1$ $ g$ of ice, then the resultant temperature of the mixture is
[1999]
(a) $270^{\circ} C$
(b) $230^{\circ} C$
(c) $100^{\circ} C$
(d) $50^{\circ} C$
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Answer:
Correct Answer: 36.(c)
Solution:
- (c) Heat required by ice at $0^{\circ} C$ to reach a temperature of $100^{\circ} C=m L+m c \Delta \theta$
$=1 \times 80+1 \times 1 \times(100-0)=180$ $ cal$
Heat available with $1 $ $g$ steam to condense into $1 $ $g$ of water at $100^{\circ} C=536 $ $cal$.
Obviously the whole steam will not be condensed and ice will attain a temperature of $100^{\circ} C$; so the temperature of mixture $=100^{\circ} C$.
BETA
