Thermodynamics Ques 2
2. The efficiency of a Carnot engine operating between the temperatures of $100^{\circ} \mathrm{C}$ and $-23^{\circ} \mathrm{C}$ will be
[1997]
(a) $\frac{100+23}{100}$
(b) $\frac{100-23}{100}$
(c) $\frac{373+250}{373}$
(d) $\frac{373-250}{373}$
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Answer:
Correct Answer: 2.(d)
Solution: (d) $\eta=1-\frac{T_1}{T_2} $
$ T_1=-23^{\circ} \mathrm{C}=250 \mathrm{K}, T_2=100^{\circ} \mathrm{C}=373 \mathrm{K} $
$ \eta=1-\frac{250}{373}=\frac{373-250}{373}$
BETA
