Thermodynamics Ques 48

48. The internal energy change in a system that has absorbed $2$ kcals of heat and done $500$ $J$ of work is:

[2009]

(a) $6400 $ $J$

(b) $5400 $ $J$

(c) $7900 $ $J$

(d) $8900 $ $J$

Show Answer

Answer:

Correct Answer: 48.(c)

Solution:

  1. (c) According to first law of thermodynamics

$Q=\Delta U+W$

$\Delta U=Q-W$

$=2 \times 4.2 \times 1000-500=8400-500$

$=7900 $ $J$



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