Wave Optics Ques 13
13. In Young’s double slit experiment carried out with light of wavelength $(\lambda)=5000 $ $\AA$, the distance between the slits is $0.2$ $ mm$ and the screen is at $200$ $ cm$ from the slits. The central maximum is at $x=0$. The third maximum (taking the central maximum as zeroth maximum) will be at $x$ equal to
[1992]
(a) $1.67 $ $cm$
(b) $1.5 $ $cm$
(c) $0.5 $ $cm$
(d) $5.0 $ $cm$
Show Answer
Answer:
Correct Answer: 13.(b)
Solution:
- (b) $x=(n) \lambda \frac{D}{d}=3 \times 5000 \times 10^{-10} \times \frac{2}{0.2 \times 10^{-3}}$
$ =1.5 \times 10^{-2} m=1.5$ $ cm $
BETA
