Wave Optics Ques 3
3. The angular resolution of a $10 \mathrm{cm}$ diameter telescope at a wavelength of $5000 $ $\AA$ is of the order of
[2005]
(a) $10^6 $ $\mathrm{rad}$
(b) $10^{-2} $ $\mathrm{rad}$
(c) $10^{-4} $ $\mathrm{rad}$
(d) $10^{-6} $ $\mathrm{rad}$
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Answer:
Correct Answer: 3.(d)
Solution: (d) $\delta \phi=1.22 \frac{\lambda}{D}=1.22 \frac{5000 \times 10^{-10}}{10 \times 10^{-2}}=6.1 \times 10^{-6} $
$ \therefore \text { Order }=10^{-6} $
BETA
