Work Energy And Power Ques 71
71. A force $F$ acting on an object varies with distance $x$ as shown here. The force is in $N$ and $x$ in $m$. The work done by the force in moving the object from $x=0$ to $x=6 m$ is
[2005]
(a) $18.0 J$
(b) $13.5 J$
(c) $9.0 J$
(d) $4.5 J$
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Answer:
Correct Answer: 71.(b)
Solution:
- (b)
Work done $=$ area under F- $x$ graph
$=$ area of trapezium $OABC$
$=\frac{1}{2}(3+6)(3)=13.5 J$
BETA
