PYQ NEET- ରାସାୟନିକ ଗତିବିଜ୍ଞାନ L-4

ପ୍ରଶ୍ନ: ଏକ ରାସାୟନିକ ପ୍ରତିକ୍ରିୟା ପାଇଁ#

$$ 4 \mathrm{~A}+3 \mathrm{~B} \rightarrow 6 \mathrm{C}+9 \mathrm{D} $$

$C$ ର ଗଠନ ହାର ହେଉଛି $6 \times 10^{-2} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}$ ଏବଂ A ର ଅଦୃଶ୍ୟ ହେବାର ହାର ହେଉଛି $4 \times 10^{-2} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}$। ପ୍ରତିକ୍ରିୟାର ହାର ଏବଂ 10 ସେକେଣ୍ଡର ବ୍ୟବଧାନରେ ବ୍ୟବହୃତ $B$ ର ପରିମାଣ, ଯଥାକ୍ରମେ ହେବ:

A) $10 \times 10^{-2} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}$ ଏବଂ $30 \times 10^{-2} \mathrm{~mol} \mathrm{~L}^{-1}$

B) $1 \times 10^{-2} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}$ ଏବଂ $30 \times 10^{-2} \mathrm{~mol} \mathrm{~L}^{-1}$

C) $10 \times 10^{-2} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}$ ଏବଂ $10 \times 10^{-2} \mathrm{~mol} \mathrm{~L}^{-1}$

D) $1 \times 10^{-2} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}$ ଏବଂ $10 \times 10^{-2} \mathrm{~mol} \mathrm{~L}^{-1}$

ଉତ୍ତର: $1 \times 10^{-2} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}$ ଏବଂ $30 \times 10^{-2} \mathrm{~mol} \mathrm{~L}^{-1}$#