ଏକ କୋଇଲ ସହିତ ସଂଯୁକ୍ତ ଆଲୋକପଥର ଫ୍ଲକ୍ସ ସମୀକରଣ ଦିଆଯାଇଛି: ΦB = 4t² + 3t + 1.
t = 2 ସେକେଣ୍ଡରେ ଆଲୋକ କ୍ଷେତ୍ର ଜାଣିବା ପାଇଁ, ଆମେ ସମୀକରଣକୁ t = 2 ସେକେଣ୍ଡରେ ମୂଲ୍ୟାଙ୍କନ କରୁଛୁ:
dB/dt = d/dt(4t² + 3t + 1) = 8t + 3
t = 2 ସେକେଣ୍ଡରେ, dB/dt = 8(2) + 3 = 14.
ଅତଏବ, t = 2 ସେକେଣ୍ଡରେ ଆଲୋକ କ୍ଷେତ୍ର 14 T ହେଉଛି।
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