PYQ NEET- ରିଡୋକ୍ସ ପ୍ରତିକ୍ରିୟାଗତ୍ମକ ପ୍ରତିଷ୍ଠାନାଧିକାରୀ ଲାୟାନ୍ତିକା ଲ-7

ପ୍ରଶ୍ନ: $298 \mathrm{~K}$ ରେ, $\mathrm{Cu}^{2+} / \mathrm{Cu}, \mathrm{Zn}^{2+} / \mathrm{Zn}, \mathrm{Fe}^{2+} / \mathrm{Fe}$ ଏବଂ $\mathrm{Ag}^{+} / \mathrm{Ag}$ ର ଆଦର୍ଶ ଇଲେକ୍ଟ୍ରୋଡ୍ ପରିମାଣ ହେଉଛି 0.34 $\mathrm{V},-0.76 \mathrm{~V},-0.44 \mathrm{~V}$ ଏବଂ $0.80 \mathrm{~V}$, ଯାହା ଆବଶ୍ୟକତାରେ ଏକାଧିକ ହୋଇଥାଏ। ଆଦର୍ଶ ଇଲେକ୍ଟ୍ରୋଡ୍ ପରିମାଣ ଆଧାରରେ, ନିମ୍ନଲିଖିତ ପ୍ରତିକ୍ରିୟା କେଉଁଟି ଘଟିପାରିବ ନାହିଁ ତାହା ଅନୁମାନ କରନ୍ତୁ? (2022)#

A) $\mathrm{FeSO}_4(\mathrm{aq})+\mathrm{Zn}(\mathrm{s}) \rightarrow \mathrm{ZnSO}_4(\mathrm{aq})+\mathrm{Fe}(\mathrm{s})$

B) $2 \mathrm{CuSO}_4(\mathrm{aq})+2 \mathrm{Ag}(\mathrm{s}) \rightarrow 2 \mathrm{Cu}(\mathrm{s})+\mathrm{Ag}_2 \mathrm{SO}_4(\mathrm{aq})$ $\mathrm

C) $\mathrm{CuSO}_4(\mathrm{aq})+\mathrm{Zn}(\mathrm{s}) \rightarrow \mathrm{ZnSO}_4(\mathrm{aq})+\mathrm{Cu}(\mathrm{s})$

D) $\mathrm{CuSO}_4(\mathrm{aq})+\mathrm{Fe}(\mathrm{s}) \rightarrow \mathrm{FeSO}_4(\mathrm{aq})+\mathrm{Cu}(\mathrm{s})$

ଉତ୍ତର: $2 \mathrm{CuSO}_4(\mathrm{aq})+2 \mathrm{Ag}(\mathrm{s}) \rightarrow 2 \mathrm{Cu}(\mathrm{s})+\mathrm{Ag}_2 \mathrm{SO}_4(\mathrm{aq})$ $\mathrm#