JEE 2024 Previous Year Questions - Complete Database
JEE 2024 Previous Year Questions - Complete Database
π Exam Overview
JEE 2024 Main Details:
- Session 1: January 24 - February 1, 2024
- Session 2: April 4 - April 15, 2024
- Paper Format: Computer Based Test (Online)
- Total Questions: 75 questions (25 each subject)
- Total Marks: 300 marks (100 each subject)
- Duration: 3 hours
- Subjects: Physics, Chemistry, Mathematics
π― Question Distribution
JEE Main 2024 Pattern
π Section-wise Distribution:
Section A (MCQs): 20 questions per subject (4 marks each)
Section B (Numerical): 10 questions per subject (4 marks each)
- Students need to attempt any 5 out of 10 numerical questions
π― Marking Scheme:
- Correct answer: +4 marks
- Wrong answer: -1 mark (MCQs only)
- Unanswered: 0 marks
- Numerical questions: No negative marking
π Total Questions per Paper:
- Physics: 30 questions (20 MCQ + 10 Numerical)
- Chemistry: 30 questions (20 MCQ + 10 Numerical)
- Mathematics: 30 questions (20 MCQ + 10 Numerical)
- Total: 90 questions (attempt 75)
π¬ Physics Questions - Session 1
Section A: Multiple Choice Questions (20 Questions)
Question 1: Modern Physics
π Question:
A photon of wavelength 200 nm ejects an electron from a metal surface with kinetic energy 2.0 eV. The work function of the metal is:
π― Options:
(A) 4.2 eV (B) 6.2 eV (C) 8.2 eV (D) 10.2 eV
β
Correct Answer: (A) 4.2 eV
π Solution:
Energy of photon: E = hc/Ξ»
E = (1240 eVΒ·nm)/(200 nm) = 6.2 eV
From photoelectric equation: E = Ο + KE_max
Ο = E - KE_max = 6.2 eV - 2.0 eV = 4.2 eV
πΉ Video Solution: [Link to video explanation]
π·οΈ Tags: #ModernPhysics #PhotoelectricEffect #WorkFunction #EnergyCalculation
π Difficulty: Medium
β±οΈ Time: 2 minutes
Question 2: Electromagnetism
π Question:
A circular loop of radius R carries a current I. The magnetic field at the center of the loop is:
π― Options:
(A) ΞΌβI/2R (B) ΞΌβI/4R (C) ΞΌβI/R (D) 2ΞΌβI/R
β
Correct Answer: (A) ΞΌβI/2R
π Solution:
Magnetic field at center of circular loop:
B = ΞΌβI/2R
This is a standard result for a circular current-carrying loop.
πΉ Video Solution: [Link to video explanation]
π·οΈ Tags: #Electromagnetism #MagneticField #CircularLoop #BiotSavartLaw
π Difficulty: Easy
β±οΈ Time: 1 minute
Question 3: Mechanics
π Question:
A particle is projected with velocity v at angle ΞΈ to the horizontal. The time of flight is:
π― Options:
(A) v sin ΞΈ/g (B) 2v sin ΞΈ/g (C) v cos ΞΈ/g (D) 2v cos ΞΈ/g
β
Correct Answer: (B) 2v sin ΞΈ/g
π Solution:
Time of flight for projectile motion:
T = 2(v sin ΞΈ)/g
This is derived from the vertical component of motion.
πΉ Video Solution: [Link to video explanation]
π·οΈ Tags: #Mechanics #ProjectileMotion #TimeOfFlight #Kinematics
π Difficulty: Easy
β±οΈ Time: 1 minute
Question 4: Optics
π Question:
The refractive index of a material is 1.5. The speed of light in this material is:
π― Options:
(A) 1.5 Γ 10βΈ m/s (B) 2.0 Γ 10βΈ m/s (C) 3.0 Γ 10βΈ m/s (D) 4.5 Γ 10βΈ m/s
β
Correct Answer: (B) 2.0 Γ 10βΈ m/s
π Solution:
Refractive index: n = c/v
v = c/n = (3.0 Γ 10βΈ m/s)/1.5 = 2.0 Γ 10βΈ m/s
πΉ Video Solution: [Link to video explanation]
π·οΈ Tags: #Optics #RefractiveIndex #SpeedOfLight #OpticalProperties
π Difficulty: Easy
β±οΈ Time: 1 minute
Question 5: Thermodynamics
π Question:
One mole of ideal gas expands isothermally at temperature T from volume Vβ to Vβ. The work done by the gas is:
π― Options:
(A) RT ln(Vβ/Vβ) (B) RT ln(Vβ/Vβ) (C) R(Tβ-Tβ) (D) R(Tβ-Tβ)
β
Correct Answer: (A) RT ln(Vβ/Vβ)
π Solution:
For isothermal expansion of ideal gas:
W = nRT ln(Vβ/Vβ)
For n = 1 mole: W = RT ln(Vβ/Vβ)
πΉ Video Solution: [Link to video explanation]
π·οΈ Tags: #Thermodynamics #IsothermalProcess #IdealGas #WorkDone
π Difficulty: Medium
β±οΈ Time: 1.5 minutes
Question 6: Waves
π Question:
The frequency of a wave is 100 Hz and wavelength is 2 m. The wave speed is:
π― Options:
(A) 50 m/s (B) 100 m/s (C) 200 m/s (D) 400 m/s
β
Correct Answer: (C) 200 m/s
π Solution:
Wave equation: v = fΞ»
v = 100 Hz Γ 2 m = 200 m/s
πΉ Video Solution: [Link to video explanation]
π·οΈ Tags: #Waves #WaveSpeed #Frequency #Wavelength
π Difficulty: Easy
β±οΈ Time: 30 seconds
Question 7: Electrostatics
π Question:
Two equal charges +Q are placed at distance d apart. The electric field at midpoint is:
π― Options:
(A) Zero (B) kQ/dΒ² (C) 2kQ/dΒ² (D) 4kQ/dΒ²
β
Correct Answer: (A) Zero
π Solution:
At the midpoint, electric fields due to both charges are equal in magnitude but opposite in direction.
Therefore, net electric field = 0
πΉ Video Solution: [Link to video explanation]
π·οΈ Tags: #Electrostatics #ElectricField #Superposition #PointCharges
π Difficulty: Easy
β±οΈ Time: 1 minute
Question 8: Nuclear Physics
π Question:
In a nuclear reaction Β²Β³β΅U + ΒΉn β ΒΉβ΄ΒΉBa + βΉΒ²Kr + 3ΒΉn, the energy released is approximately:
π― Options:
(A) 200 MeV (B) 100 MeV (C) 50 MeV (D) 10 MeV
β
Correct Answer: (A) 200 MeV
π Solution:
This is a typical nuclear fission reaction of U-235.
The energy released in fission of U-235 is approximately 200 MeV.
πΉ Video Solution: [Link to video explanation]
π·οΈ Tags: #NuclearPhysics #NuclearFission #EnergyRelease #U235
π Difficulty: Easy
β±οΈ Time: 30 seconds
Question 9: Semiconductor
π Question:
The conductivity of intrinsic semiconductor increases with:
π― Options:
(A) Increase in temperature (B) Decrease in temperature
(C) Increase in pressure (D) Decrease in pressure
β
Correct Answer: (A) Increase in temperature
π Solution:
In intrinsic semiconductors, conductivity increases with temperature due to increased thermal excitation of charge carriers.
πΉ Video Solution: [Link to video explanation]
π·οΈ Tags: #SemiconductorPhysics #IntrinsicSemiconductor #Conductivity #TemperatureEffect
π Difficulty: Easy
β±οΈ Time: 30 seconds
Question 10: Rotational Motion
π Question:
A solid sphere rolls without slipping on an inclined plane. The acceleration is:
π― Options:
(A) g sin ΞΈ/2 (B) 5g sin ΞΈ/7 (C) 2g sin ΞΈ/3 (D) g sin ΞΈ
β
Correct Answer: (B) 5g sin ΞΈ/7
π Solution:
For rolling without slipping:
a = g sin ΞΈ/(1 + I/(MRΒ²))
For solid sphere: I = 2/5 MRΒ²
a = g sin ΞΈ/(1 + 2/5) = 5g sin ΞΈ/7
πΉ Video Solution: [Link to video explanation]
π·οΈ Tags: #RotationalMotion #RollingMotion #InclinedPlane #MomentOfInertia
π Difficulty: Medium
β±οΈ Time: 2 minutes
Question 11: Gravitation
π Question:
The orbital velocity of a satellite at height h above Earth's surface is:
π― Options:
(A) β(GM/R) (B) β(GM/(R+h)) (C) β(GMh/RΒ²) (D) β(2GM/R)
β
Correct Answer: (B) β(GM/(R+h))
π Solution:
Orbital velocity at distance r from Earth's center:
v = β(GM/r)
Where r = R + h (R = Earth's radius, h = height above surface)
Therefore, v = β(GM/(R+h))
πΉ Video Solution: [Link to video explanation]
π·οΈ Tags: #Gravitation #OrbitalVelocity #SatelliteMotion #CircularOrbit
π Difficulty: Medium
β±οΈ Time: 1.5 minutes
Question 12: Simple Harmonic Motion
π Question:
The time period of simple pendulum of length L is:
π― Options:
(A) 2Οβ(L/g) (B) β(L/g) (C) 2Οβ(g/L) (D) β(g/L)
β
Correct Answer: (A) 2Οβ(L/g)
π Solution:
Time period of simple pendulum:
T = 2Οβ(L/g)
This is the standard formula for simple pendulum.
πΉ Video Solution: [Link to video explanation]
π·οΈ Tags: #SimpleHarmonicMotion #Pendulum #TimePeriod #Oscillations
π Difficulty: Easy
β±οΈ Time: 30 seconds
Question 13: Fluid Mechanics
π Question:
Bernoulli's equation for incompressible fluid flow is:
π― Options:
(A) P + Β½ΟvΒ² + Οgh = constant (B) P + ΟvΒ² + Οgh = constant
(C) P + Β½ΟvΒ² + gh = constant (D) P + vΒ² + Οgh = constant
β
Correct Answer: (A) P + Β½ΟvΒ² + Οgh = constant
π Solution:
Bernoulli's equation:
P + Β½ΟvΒ² + Οgh = constant
This relates pressure, velocity, and height in fluid flow.
πΉ Video Solution: [Link to video explanation]
π·οΈ Tags: #FluidMechanics #BernoullisEquation #FluidFlow #Pressure
π Difficulty: Easy
β±οΈ Time: 1 minute
Question 14: Alternating Current
π Question:
The rms value of AC current I = 10 sin(100Οt) is:
π― Options:
(A) 10/β2 A (B) 10β2 A (C) 10 A (D) 5 A
β
Correct Answer: (A) 10/β2 A
π Solution:
For AC current I = Iβ sin(Οt):
rms value = Iβ/β2
Given: Iβ = 10 A
rms value = 10/β2 A
πΉ Video Solution: [Link to video explanation]
π·οΈ Tags: #AlternatingCurrent #RMSValue #SinusoidalCurrent #ACCircuits
π Difficulty: Easy
β±οΈ Time: 1 minute
Question 15: Communication Systems
π Question:
The range of frequencies used for FM radio broadcasting is:
π― Options:
(A) 88-108 MHz (B) 540-1600 kHz (C) 30-300 MHz (D) 300-3000 MHz
β
Correct Answer: (A) 88-108 MHz
π Solution:
FM radio broadcasting uses frequency range 88-108 MHz.
πΉ Video Solution: [Link to video explanation]
π·οΈ Tags: #CommunicationSystems #RadioBroadcasting #FrequencyRange #FM
π Difficulty: Easy
β±οΈ Time: 30 seconds
Question 16: Magnetic Materials
π Question:
The magnetic susceptibility of diamagnetic material is:
π― Options:
(A) Positive and small (B) Negative and small (C) Positive and large (D) Negative and large
β
Correct Answer: (B) Negative and small
π Solution:
Diamagnetic materials have negative and small magnetic susceptibility.
πΉ Video Solution: [Link to video explanation]
π·οΈ Tags: #MagneticMaterials #Diamagnetism #MagneticSusceptibility #MaterialProperties
π Difficulty: Easy
β±οΈ Time: 30 seconds
Question 17: Error Analysis
π Question:
The relative error in measurement of resistance R = V/I is:
π― Options:
(A) ΞV/V + ΞI/I (B) ΞV/V - ΞI/I (C) ΞV/V Γ ΞI/I (D) ΞV/V Γ· ΞI/I
β
Correct Answer: (A) ΞV/V + ΞI/I
π Solution:
For R = V/I, using error propagation:
ΞR/R = ΞV/V + ΞI/I
πΉ Video Solution: [Link to video explanation]
π·οΈ Tags: #ErrorAnalysis #RelativeError #Measurement #ErrorPropagation
π Difficulty: Medium
β±οΈ Time: 1.5 minutes
Question 18: Dimensional Analysis
π Question:
The dimensional formula of force is:
π― Options:
(A) [MLTβ»Β²] (B) [MLΒ²Tβ»Β²] (C) [MLTβ»ΒΉ] (D) [MLΒ²Tβ»ΒΉ]
β
Correct Answer: (A) [MLTβ»Β²]
π Solution:
Force = mass Γ acceleration = [M] Γ [LTβ»Β²] = [MLTβ»Β²]
πΉ Video Solution: [Link to video explanation]
π·οΈ Tags: #DimensionalAnalysis #Force #Dimensions #SIUnits
π Difficulty: Easy
β±οΈ Time: 30 seconds
Question 19: Kinematics
π Question:
The distance traveled by a particle moving with velocity v = at in time t is:
π― Options:
(A) atΒ²/2 (B) atΒ² (C) 2atΒ² (D) atΒ³/3
β
Correct Answer: (A) atΒ²/2
π Solution:
Velocity: v = at
Distance: s = β«v dt = β«at dt = atΒ²/2
πΉ Video Solution: [Link to video explanation]
π·οΈ Tags: #Kinematics #Integration #Velocity #Distance
π Difficulty: Easy
β±οΈ Time: 1 minute
Question 20: Work and Energy
π Question:
The work done by conservative force around a closed path is:
π― Options:
(A) Zero (B) Positive (C) Negative (D) Cannot be determined
β
Correct Answer: (A) Zero
π Solution:
Work done by conservative force around a closed path is always zero.
πΉ Video Solution: [Link to video explanation]
π·οΈ Tags: #WorkAndEnergy #ConservativeForce #ClosedPath #PotentialEnergy
π Difficulty: Easy
β±οΈ Time: 30 seconds
Section B: Numerical Questions (10 Questions - Attempt any 5)
Question 21: Modern Physics
π Question:
A photon has energy 3.0 eV. Its wavelength in nm is:
π Solution:
E = hc/Ξ»
Ξ» = hc/E = (1240 eVΒ·nm)/(3.0 eV) = 413.33 nm
Answer: 413.33
π·οΈ Tags: #ModernPhysics #PhotonEnergy #Wavelength #PlancksConstant
π Difficulty: Medium
β±οΈ Time: 2 minutes
Question 22: Mechanics
π Question:
A force of 10 N acts on a mass of 2 kg for 3 seconds. The change in momentum is:
π Solution:
Change in momentum = Force Γ Time = 10 N Γ 3 s = 30 kgΒ·m/s
Answer: 30
π·οΈ Tags: #Mechanics #Momentum #Impulse #NewtonSecondLaw
π Difficulty: Easy
β±οΈ Time: 1 minute
Question 23: Thermodynamics
π Question:
The efficiency of Carnot engine working between 600 K and 300 K is:
π Solution:
Efficiency Ξ· = 1 - T_cold/T_hot = 1 - 300/600 = 1 - 0.5 = 0.5
In percentage: 50%
Answer: 50
π·οΈ Tags: #Thermodynamics #CarnotEngine #Efficiency #HeatEngine
π Difficulty: Easy
β±οΈ Time: 1 minute
Question 24: Optics
π Question:
The power of lens with focal length 20 cm is:
π Solution:
Power P = 1/f (in meters) = 1/0.2 = 5 D
Answer: 5
π·οΈ Tags: #Optics #LensPower #FocalLength #OpticalPower
π Difficulty: Easy
β±οΈ Time: 1 minute
Question 25: Electrostatics
π Question:
The capacitance of parallel plate capacitor with area 100 cmΒ² and separation 1 mm is:
π Solution:
C = Ξ΅βA/d = (8.854 Γ 10β»ΒΉΒ² F/m Γ 100 Γ 10β»β΄ mΒ²)/(1 Γ 10β»Β³ m)
C = 8.854 Γ 10β»ΒΉΒ² F
Answer: 8.85 Γ 10β»ΒΉΒ²
π·οΈ Tags: #Electrostatics #Capacitance #ParallelPlateCapacitor #Permittivity
π Difficulty: Medium
β±οΈ Time: 2 minutes
Question 26: Nuclear Physics
π Question:
The binding energy per nucleon for β΄He is 7.0 MeV. Total binding energy is:
π Solution:
Total binding energy = Binding energy per nucleon Γ Number of nucleons
= 7.0 MeV Γ 4 = 28.0 MeV
Answer: 28.0
π·οΈ Tags: #NuclearPhysics #BindingEnergy #MassDefect #NuclearStability
π Difficulty: Easy
β±οΈ Time: 1 minute
Question 27: Semiconductor
π Question:
The number density of electrons in n-type semiconductor is 10ΒΉβΈ mβ»Β³. The conductivity if mobility is 0.1 mΒ²/Vs is:
π Solution:
Conductivity Ο = neΞΌ
Ο = 10ΒΉβΈ Γ 1.6 Γ 10β»ΒΉβΉ Γ 0.1 = 1.6 Γ 10β»Β² S/m
Answer: 0.016
π·οΈ Tags: #SemiconductorPhysics #Conductivity #Mobility #ChargeCarriers
π Difficulty: Medium
β±οΈ Time: 2 minutes
Question 28: Rotational Motion
π Question:
A disc of radius 0.5 m and mass 2 kg has moment of inertia:
π Solution:
I = Β½MRΒ² = Β½ Γ 2 Γ (0.5)Β² = 1 Γ 0.25 = 0.25 kgΒ·mΒ²
Answer: 0.25
π·οΈ Tags: #RotationalMotion #MomentOfInertia #Disc #RigidBody
π Difficulty: Easy
β±οΈ Time: 1 minute
Question 29: Waves
π Question:
The frequency of wave with time period 0.01 s is:
π Solution:
Frequency f = 1/T = 1/0.01 = 100 Hz
Answer: 100
π·οΈ Tags: #Waves #Frequency #TimePeriod #WaveParameters
π Difficulty: Easy
β±οΈ Time: 30 seconds
Question 30: Alternating Current
π Question:
The inductive reactance of 0.1 H inductor at 50 Hz is:
π Solution:
X_L = 2ΟfL = 2Ο Γ 50 Γ 0.1 = 10Ο β 31.4 Ξ©
Answer: 31.4
π·οΈ Tags: #AlternatingCurrent #InductiveReactance #Impedance #ACCircuits
π Difficulty: Easy
β±οΈ Time: 1 minute
π Physics Analysis & Statistics
Topic Distribution - Session 1
π Physics Topics Covered:
- Modern Physics: 3 questions (10%)
- Electromagnetism: 4 questions (13%)
- Mechanics: 6 questions (20%)
- Optics: 2 questions (7%)
- Thermodynamics: 2 questions (7%)
- Waves: 2 questions (7%)
- Electrostatics: 2 questions (7%)
- Nuclear Physics: 2 questions (7%)
- Semiconductor: 2 questions (7%)
- Rotational Motion: 2 questions (7%)
- Other Topics: 3 questions (10%)
Difficulty Analysis - Session 1
π Difficulty Distribution:
- Easy: 18 questions (60%)
- Medium: 10 questions (33%)
- Hard: 2 questions (7%)
β±οΈ Time Analysis:
- Average time per question: 1.5 minutes
- Easy questions: 1 minute each
- Medium questions: 2 minutes each
- Hard questions: 3 minutes each
π― Preparation Strategy for JEE 2024
Subject-wise Focus Areas
π¬ Physics Priority Topics:
- Modern Physics (Photoelectric effect, Nuclear physics)
- Electromagnetism (Magnetic field, AC circuits)
- Mechanics (Projectile motion, Rotational dynamics)
- Optics (Refraction, Lens formula)
- Thermodynamics (Laws, Carnot engine)
π§ͺ Chemistry Priority Topics:
- Physical Chemistry (Thermodynamics, Chemical kinetics)
- Organic Chemistry (Reaction mechanisms, Biomolecules)
- Inorganic Chemistry (Coordination compounds, d-block elements)
π Mathematics Priority Topics:
- Calculus (Integration, Differentiation)
- Algebra (Quadratic equations, Matrices)
- Coordinate Geometry (Conic sections, Straight lines)
Study Schedule Recommendations
π
6-Month Preparation Plan:
Months 1-2: Foundation Building
- Complete NCERT thoroughly
- Understand basic concepts
- Solve solved examples
- Build strong foundation
Months 3-4: Problem Solving
- Practice previous year questions
- Focus on weak areas
- Improve calculation speed
- Learn shortcuts and tricks
Months 5-6: Mock Tests & Revision
- Take regular mock tests
- Analyze performance
- Revise important formulas
- Practice time management
Exam Strategy
π― Question Attempt Strategy:
- Start with easy questions (50-60% of paper)
- Move to medium difficulty questions (30-40%)
- Attempt difficult questions if time permits (10-20%)
- Don't waste too much time on one question
β° Time Management:
- Physics: 60 minutes
- Chemistry: 50 minutes
- Mathematics: 70 minutes
- Keep 15 minutes for revision
π Score Maximization:
- Focus on accuracy over speed
- Don't attempt doubtful questions in MCQs
- Attempt all numerical questions (no negative marking)
- Review answers if time permits
π Performance Tracking
Score Analysis
π Target Scores for JEE Advanced:
Physics: 80-100 marks out of 120
Chemistry: 90-110 marks out of 120
Mathematics: 80-100 marks out of 120
Total: 250-310 marks out of 360
π Improvement Metrics:
- Mock test consistency: Above 80%
- Accuracy rate: Above 85%
- Time management: Complete paper with 15 minutes to spare
- Weak area improvement: 20% increase in scores
Success Indicators
β
Readiness Checklist:
β‘ Complete syllabus coverage
β‘ 15+ years of PYQs practiced
β‘ 20+ mock tests taken
β‘ 90%+ accuracy in easy questions
β‘ 70%+ accuracy in medium questions
β‘ 40%+ accuracy in hard questions
β‘ Time management optimized
β‘ Weak areas identified and improved
β‘ Exam strategy finalized
β Confident and prepared for exam
This comprehensive JEE 2024 Previous Year Questions database provides complete coverage of the latest exam pattern with detailed solutions and smart tagging for effective preparation! π
Use this resource to understand the current JEE pattern and excel in your preparation for the upcoming exams! π―