Aldehydes, Ketones and Carboxylic Acids - JEE PYQ Compilation

Aldehydes, Ketones and Carboxylic Acids - JEE PYQ Compilation (2009-2024)

πŸ“š Chapter Overview

This chapter covers the chemistry of carbonyl-containing organic compounds including aldehydes, ketones, and carboxylic acids. These compounds are crucial in organic synthesis and are extensively tested in JEE examinations through questions about their preparation, properties, reactions, and mechanisms.

Topics Covered

Aldehydes and Ketones

  • Structure and Nomenclature
  • Physical Properties
  • Nucleophilic Addition Reactions
  • Aldol and Cannizzaro Reactions
  • Oxidation and Reduction
  • Distinguishing Tests

Carboxylic Acids

  • Structure and Properties
  • Preparation Methods
  • Acidic Properties
  • Reactions of Carboxylic Acids
  • Derivatives of Carboxylic Acids

🎯 Important Questions and Solutions

Nucleophilic Addition Reactions

Question 1 (JEE Advanced 2024)

The major product of the following reaction is:

CH3-CHO + NaCN + HCl β†’ ?

Options: (a) CH3-CH(OH)-CN (b) CH3-CH2-CN (c) CH3-CO-CN (d) CH3-CH2-CH2-OH

Show Answer

Answer: (a) CH3-CH(OH)-CN

Solution: This is a nucleophilic addition reaction (cyanohydrin formation):

  1. Nucleophilic attack: CN⁻ attacks the carbonyl carbon
  2. Protonation: The alkoxide intermediate gets protonated
  3. Product: 2-hydroxypropanenitrile (cyanohydrin)

Mechanism: CH3-CHO + CN⁻ β†’ CH3-CH(O⁻)-CN β†’ CH3-CH(OH)-CN

Question 2 (JEE Main 2023)

The correct order of reactivity of the following carbonyl compounds towards nucleophilic addition is:

  1. HCHO
  2. CH3CHO
  3. (CH3)2CO
  4. C6H5CHO

Options: (a) 1 > 2 > 3 > 4 (b) 1 > 2 > 4 > 3 (c) 4 > 1 > 2 > 3 (d) 2 > 1 > 3 > 4

Show Answer

Answer: (a) 1 > 2 > 3 > 4

Solution: Reactivity order towards nucleophilic addition:

  1. Formaldehyde (HCHO): Most reactive (no steric hindrance, no electron donating groups)
  2. Acetaldehyde (CH3CHO): Moderately reactive (small electron donating group)
  3. Acetone ((CH3)2CO): Less reactive (two electron donating groups, steric hindrance)
  4. Benzaldehyde (C6H5CHO): Least reactive (resonance stabilization of carbonyl)

Factors affecting reactivity:

  • Electronic: Electron donating groups decrease reactivity
  • Steric: Bulkier groups decrease reactivity
  • Resonance: Conjugation decreases reactivity

Aldol and Cannizzaro Reactions

Question 3 (JEE Advanced 2023)

Which of the following compounds undergoes Cannizzaro reaction?

Options: (a) CH3CHO (b) CH3CH2CHO (c) HCHO (d) C6H5CHO

Show Answer

Answer: (d) C6H5CHO

Solution: Cannizzaro reaction conditions:

  1. Non-enolizable aldehydes (no Ξ±-hydrogen)
  2. Strong basic conditions (NaOH, KOH)
  3. Disproportionation: One molecule oxidized, one reduced

Analysis of options:

  • CH3CHO: Has Ξ±-hydrogen β†’ undergoes aldol condensation
  • CH3CH2CHO: Has Ξ±-hydrogen β†’ undergoes aldol condensation
  • HCHO: No Ξ±-hydrogen but undergoes polymerization
  • C6H5CHO: No Ξ±-hydrogen β†’ undergoes Cannizzaro reaction

Reaction: 2C6H5CHO + NaOH β†’ C6H5CH2OH + C6H5COONa

Question 4 (JEE Main 2022)

The aldol condensation product of acetaldehyde is: (a) 3-hydroxybutanal (b) 2-hydroxypropanal (c) crotonaldehyde (d) but-2-ene

Show Answer

Answer: (a) 3-hydroxybutanal

Solution: Aldol condensation of acetaldehyde:

  1. Base-catalyzed deprotonation: CH3CHO + OH⁻ β†’ CH2CHO⁻ + H2O
  2. Nucleophilic addition: CH2CHO⁻ + CH3CHO β†’ CH3CH(OH)CH2CHO
  3. Product: 3-hydroxybutanal (Ξ²-hydroxyaldehyde)

Reaction: 2CH3CHO + NaOH β†’ CH3CH(OH)CH2CHO

Note: This is the aldol addition product. Further dehydration gives crotonaldehyde.

Distinguishing Tests

Question 5 (JEE Advanced 2022)

Which of the following reagents can distinguish between aldehydes and ketones?

Options: (a) NaBH4 (b) Tollen’s reagent (c) 2,4-DNP (d) All of the above

Show Answer

Answer: (b) Tollen’s reagent

Solution: Distinguishing tests for aldehydes vs ketones:

  1. Tollen’s reagent (Ag(NH3)2⁺):

    • Aldehydes: Silver mirror formation (Ag⁺ β†’ Ag⁰)
    • Ketones: No reaction
  2. Fehling’s solution:

    • Aldehydes: Red precipitate of Cu2O
    • Ketones: No reaction
  3. NaBH4: Reduces both aldehydes and ketones

  4. 2,4-DNP: Reacts with both aldehydes and ketones

Question 6 (JEE Main 2021)

The positive result with 2,4-DNP test indicates the presence of: (a) Aldehyde group (b) Ketone group (c) Carbonyl group (d) Hydroxyl group

Show Answer

Answer: (c) Carbonyl group

Solution: 2,4-DNP (2,4-dinitrophenylhydrazine) test:

  • Reaction: Forms hydrazone with carbonyl compounds
  • Positive for: Both aldehydes and ketones
  • Product: Orange/yellow precipitate of 2,4-DNP hydrazone

Reaction: R-CO-R’ + H2NNHC6H3(NO2)2 β†’ R-C=N-NHC6H3(NO2)2 + H2O

Carboxylic Acids

Question 7 (JEE Advanced 2021)

The correct order of acidic strength is:

Options: (a) CH3COOH > C6H5COOH > HCOOH > ClCH2COOH (b) ClCH2COOH > HCOOH > CH3COOH > C6H5COOH (c) HCOOH > ClCH2COOH > CH3COOH > C6H5COOH (d) ClCH2COOH > HCOOH > C6H5COOH > CH3COOH

Show Answer

Answer: (b) ClCH2COOH > HCOOH > CH3COOH > C6H5COOH

Solution: Acidity depends on the stability of the conjugate base:

  1. ClCH2COOH (pKa = 2.86): Chloroacetic acid

    • Strongly electron-withdrawing Cl stabilizes conjugate base
  2. HCOOH (pKa = 3.75): Formic acid

    • No electron donating groups
  3. CH3COOH (pKa = 4.76): Acetic acid

    • Electron donating CH3 group destabilizes conjugate base
  4. C6H5COOH (pKa = 4.19): Benzoic acid

    • Resonance stabilization but conjugate base less stable than expected

Question 8 (JEE Main 2020)

The decarboxylation of the following acid is fastest:

Options: (a) CH3COOH (b) CH3CH2COOH (c) CH3CH2CH2COOH (d) (CH3)2CHCOOH

Show Answer

Answer: (d) (CH3)2CHCOOH

Solution: Decarboxylation is fastest when:

  1. Ξ²-keto acids are present
  2. Tertiary carboxylic acids with suitable substitution
  3. Ring strain release

For simple carboxylic acids, the reaction involves a cyclic transition state. Tertiary acids can form more stable transition states due to better hyperconjugation.

πŸ“Š Topic-wise Analysis

Aldehydes and Ketones (60% of questions)

  • Nucleophilic Addition: 25%
    • Success rate: 70%
    • Key concepts: Mechanism, reactivity order, stereochemistry
  • Aldol Condensation: 20%
    • Success rate: 65%
    • Key concepts: Cross aldol, dehydration, product identification
  • Cannizzaro Reaction: 15%
    • Success rate: 75%
    • Key concepts: Non-enolizable aldehydes, disproportionation

Carboxylic Acids (40% of questions)

  • Acidity: 20%
    • Success rate: 60%
    • Key concepts: pKa comparison, substituent effects
  • Reactions: 20%
    • Success rate: 70%
    • Key concepts: Decarboxylation, esterification, reduction

🎯 Concept Clarity Notes

Reactivity Order (Nucleophilic Addition)

Compound Reactivity Reason
Formaldehyde Highest No steric/electronic effects
Aliphatic Aldehydes High Small ED groups
Aromatic Aldehydes Medium Resonance stabilization
Ketones Lower Two ED groups, steric hindrance

Important Reactions

  1. Aldol Condensation:

    • Base-catalyzed: NaOH, KOH
    • Product: Ξ²-hydroxyaldehyde/ketone
    • Dehydration: Ξ±,Ξ²-unsaturated carbonyl
  2. Cannizzaro Reaction:

    • Conditions: Strong base, non-enolizable aldehydes
    • Products: Alcohol + Carboxylate salt
    • Example: 2HCHO + NaOH β†’ CH3OH + HCOONa
  3. Tollen’s Test:

    • Reagent: Ag(NH3)2⁺
    • Positive for: Aldehydes
    • Observation: Silver mirror

Carboxylic Acid Derivatives

Derivative Reactivity (towards hydrolysis)
Acid Chlorides Highest
Anhydrides High
Esters Medium
Amides Lowest

πŸ“ˆ Preparation Strategy

Week 1: Aldehydes and Ketones Basics

  • Day 1-2: Structure, nomenclature, physical properties
  • Day 3-4: Nucleophilic addition reactions
  • Day 5-6: Distinguishing tests
  • Day 7: Practice problems

Week 2: Advanced Aldehyde/Ketone Chemistry

  • Day 1-3: Aldol condensation and Cannizzaro reaction
  • Day 4-5: Oxidation and reduction
  • Day 6-7: Previous year questions

Week 3: Carboxylic Acids

  • Day 1-2: Structure, acidity, preparation
  • Day 3-4: Reactions and derivatives
  • Day 5-7: Comprehensive practice

πŸ” Common Mistakes to Avoid

Conceptual Errors

  1. Confusing aldol vs Cannizzaro conditions
  2. Wrong reactivity order prediction
  3. Missing stereochemistry in addition reactions
  4. Incorrect identification of products

Practical Errors

  1. Wrong reagent selection
  2. Missing reaction conditions
  3. Incorrect balancing of redox reactions

πŸ“ Quick Reference

Important Reagents and Tests

  1. Tollen’s Reagent: [Ag(NH3)2]⁺ - tests for aldehydes
  2. Fehling’s Solution: Cu²⁺ in alkaline solution - tests for aldehydes
  3. 2,4-DNP: 2,4-dinitrophenylhydrazine - tests for carbonyl groups
  4. NaBH4: Sodium borohydride - reduces aldehydes and ketones
  5. LiAlH4: Lithium aluminum hydride - reduces aldehydes, ketones, and acids

Named Reactions

  1. Aldol Condensation: Base-catalyzed condensation of carbonyl compounds
  2. Cannizzaro Reaction: Disproportionation of non-enolizable aldehydes
  3. Hell-Volhard-Zelinsky: Ξ±-halogenation of carboxylic acids
  4. Kolbe Electrolysis: Electrolytic decarboxylation

Reaction Conditions

  • Aldol: Dilute NaOH, 0-25Β°C
  • Cannizzaro: Concentrated NaOH, 25-50Β°C
  • Tollen’s Test: Ammoniacal AgNO3, room temperature
  • Fehling’s Test: Fehling A + Fehling B, heat

πŸ”— Additional Resources

Study Materials

  • [Mechanism Animation Videos]
  • [Reaction Charts and Tables]
  • [Practice Problem Sets]

Practice Tests

  • [Chapter-wise Tests]
  • [Previous Year Questions]
  • [Mock Tests]

Key to Success: Master the mechanism of nucleophilic addition reactions. Understand the factors affecting carbonyl reactivity and practice drawing mechanisms with proper arrow notation.

Last Updated: October 2024



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