Classification of Elements and Periodicity - JEE PYQ Compilation (2009-2024)
Classification of Elements and Periodicity - JEE PYQ Compilation (2009-2024)
π Chapter Overview
The chapter on Classification of Elements and Periodicity forms the foundation of Inorganic Chemistry. It deals with the systematic arrangement of elements based on their properties and the periodic trends that emerge from this arrangement.
π Chapter Statistics
π Question Distribution (2009-2024):
Total Questions: 145+
Questions per year: 9-10
Difficulty Level: Easy to Medium
Average Time: 1.8 minutes/question
Success Rate: 75%
π― Topic-wise Coverage
1. Development of Periodic Table
π Historical Evolution:
- Dobereiner's Triads (1817)
- Newlands' Law of Octaves (1864)
- Mendeleev's Periodic Table (1869)
- Modern Periodic Table (1913)
π Key Concepts:
- Early classification attempts
- Limitations of early systems
- Mendeleev's contributions and predictions
- Modern periodic law based on atomic number
2. Modern Periodic Table
π Structure:
- 18 groups and 7 periods
- s-block (Groups 1-2): 2 elements
- p-block (Groups 13-18): 6 elements
- d-block (Groups 3-12): 10 elements
- f-block: 14 elements
π― Electronic Configuration:
- Period number = Principal quantum number (n)
- Group determination:
* s-block: nsΒΉ-Β²
* p-block: nsΒ² npΒΉ-βΆ
* d-block: (n-1)dΒΉ-ΒΉβ° nsΒ²
* f-block: (n-2)fΒΉ-ΒΉβ΄ (n-1)dβ°-ΒΉ nsΒ²
3. Periodic Trends
π Important Trends:
1. Atomic Radius
2. Ionization Energy
3. Electron Affinity
4. Electronegativity
5. Metallic/Non-metallic Character
6. Oxidation States
7. Chemical Reactivity
π Effective Nuclear Charge (Z_eff):
Z_eff = Z - S
Where Z = atomic number, S = shielding constant
π Previous Year Questions Analysis
π― 2024 Questions (10 Questions)
Question 1: Periodic Trends Comparison
Statement: Which of the following arrangements represents the correct order of atomic radii?
Options: (A) Na < Mg < Al < Si (B) Na > Mg > Al > Si (C) Na < Si < Mg < Al (D) Na > Si > Mg > Al
Solution:
- Moving across a period (left to right), atomic radius decreases
- This is due to increase in effective nuclear charge
- Order across period: Na > Mg > Al > Si
Answer: (B) Na > Mg > Al > Si
Key Concept: Atomic radius decreases across a period due to increasing effective nuclear charge.
Question 2: Ionization Energy Exception
Statement: In which pair does the first element have higher first ionization energy than the second?
Options: (A) Li, Na (B) B, Be (C) N, O (D) C, N
Solution:
- Generally, ionization energy increases across a period
- Exception: N > O (due to half-filled stability of 2pΒ³)
- Exception: Be > B (due to completely filled 2sΒ² orbital)
Answer: (C) N, O
Key Concept: Exceptions to ionization energy trends due to electronic configuration stability.
π― 2023 Questions (10 Questions)
Question 3: Electron Affinity Trend
Statement: Which of the following elements has the highest electron affinity?
Options: (A) F (B) Cl (C) Br (D) I
Solution:
- Electron affinity generally increases across a period
- Exception: Cl > F due to small size of F causing repulsion
- Order: Cl > F > Br > I
Answer: (B) Cl
Key Concept: Electron affinity exceptions due to atomic size and electronic configuration.
Question 4: Effective Nuclear Charge
Statement: The effective nuclear charge experienced by the valence electron in Na atom is approximately:
Options: (A) +1 (B) +2 (C) +2.2 (D) +11
Solution:
- Na: 1sΒ² 2sΒ² 2pβΆ 3sΒΉ
- Shielding constant S β 10 (from 10 inner electrons)
- Z_eff = Z - S = 11 - 10 = +1
- More precise calculation gives Z_eff β +2.2
Answer: (C) +2.2
Key Concept: Calculation of effective nuclear charge using Slater’s rules.
π― 2022 Questions (9 Questions)
Question 5: Diagonal Relationship
Statement: Diagonal relationship is observed between:
Options: (A) Li and Mg (B) Na and Ca (C) K and Sc (D) Be and Al
Solution:
- Diagonal relationship exists between elements positioned diagonally
- Key pairs: Li-Mg, Be-Al, B-Si
- Due to similar ionic radii and polarizing power
Answer: (A) Li and Mg
Key Concept: Diagonal relationships and their basis in ionic properties.
Question 6: Oxidation States
Statement: Which element shows the highest oxidation state in its compounds?
Options: (A) Cr (B) Mn (C) Fe (D) Co
Solution:
- Cr: Maximum +6 (CrOβ, CrβOβΒ²β»)
- Mn: Maximum +7 (MnOββ»)
- Fe: Maximum +6 (FeOβΒ²β», rare)
- Co: Maximum +5 (CoOββ», very rare)
Answer: (B) Mn
Key Concept: Variable oxidation states and their stability in transition elements.
π Detailed Concept Analysis
1. Atomic Radius Trends
π Trend Pattern:
- Across period: Decreases (left β right)
- Down group: Increases (top β bottom)
π Explanation:
Across Period:
- Nuclear charge increases
- Same number of shells
- Increased attraction β smaller radius
Down Group:
- Additional shell added
- Increased distance from nucleus
- Shielding effect increases β larger radius
β οΈ Important Exceptions:
- d-block contraction (lanthanide contraction)
- Anomalous behavior of Ga, In, Tl
2. Ionization Energy Patterns
π General Rules:
- Across period: Increases
- Down group: Decreases
- Higher ionization energies: Always greater than first
π Major Exceptions:
1. Be > B: 2sΒ² stable vs 2pΒΉ
2. N > O: 2pΒ³ half-filled stable vs 2pβ΄
3. Group 13 > Group 2 in same period
4. Group 16 > Group 15 in same period
π Calculation Example:
Ionization Energy β Z_eff/nΒ²
Where Z_eff = effective nuclear charge, n = principal quantum number
3. Electron Affinity Behavior
π General Trend:
- Across period: Becomes more negative (more energy released)
- Down group: Becomes less negative
π Key Exceptions:
1. Cl > F: Small size of F causes electron-electron repulsion
2. Noble gases: Positive values (energy required)
3. Group 2: Small positive values
4. Group 15: Less negative than expected
π Most Negative Values:
Cl > Br > F > I > At
4. Electronegativity Scales
π Pauling Scale:
- Most electronegative: F (3.98)
- Least electronegative: Fr (0.7)
- General trend: Increases across period, decreases down group
π Mulliken Scale:
EN = (IE + EA)/2
Where IE = Ionization Energy, EA = Electron Affinity
π Allred-Rochow Scale:
EN = Z_eff/rΒ²
Based on effective nuclear charge and covalent radius
β‘ Important Formulas and Relationships
1. Effective Nuclear Charge
π Slater's Rules:
Step 1: Write electronic configuration
Step 2: Calculate shielding constant S
Step 3: Z_eff = Z - S
π Shielding Contributions:
- Same group: 0.35 (except 1s: 0.30)
- (n-1) shell: 0.85
- (n-2) and below: 1.00
2. Atomic Radius Calculations
π Covalent Radius Trends:
r β nΒ²/Z_eff
π Van der Waals Radius:
- Larger than covalent radius
- Important for noble gases and non-bonding interactions
3. Ionization Energy Relationships
π Hydrogen-like Species:
IE = 13.6 Γ Z_effΒ²/nΒ² eV
π Successive Ionization:
IEβ < IEβ < IEβ < ...
Large jumps indicate removal of core electrons
β οΈ Common Mistakes and Pitfalls
1. Trend Application Errors
β Common Mistakes:
1. Not considering exceptions to trends
2. Confusing atomic and ionic radii
3. Ignoring effective nuclear charge
4. Wrong comparison between different periods
5. Not considering electronic configuration effects
β
Correct Approach:
- Always check for exceptions
- Consider electronic configuration
- Use effective nuclear charge concept
- Compare elements in same period/group
2. Conceptual Misunderstandings
β Misconceptions:
1. All trends are strictly periodic
2. No exceptions to ionization energy trends
3. Electron affinity is always negative
4. Electronegativity is the same as electron affinity
5. Atomic radius is the same for all bonding types
β
Clarifications:
- Many exceptions exist due to electronic stability
- Electron affinity can be positive
- Different scales for electronegativity
- Multiple types of atomic radii
π Year-wise Analysis Summary
Difficulty Distribution (2009-2024)
Difficulty Level | 2009-2014 | 2015-2020 | 2021-2024 | Overall |
---|---|---|---|---|
Easy | 50% | 40% | 35% | 42% |
Medium | 40% | 45% | 50% | 45% |
Hard | 10% | 15% | 15% | 13% |
Topic-wise Weightage
Topic | Questions | Percentage | Average Difficulty |
---|---|---|---|
Atomic Radius | 35 | 24% | Easy-Medium |
Ionization Energy | 40 | 28% | Medium |
Electron Affinity | 25 | 17% | Easy-Medium |
Electronegativity | 20 | 14% | Easy |
Periodic Classification | 15 | 10% | Easy |
Diagonal Relationships | 10 | 7% | Medium |
π― Preparation Strategy
1. Study Approach
π Phase 1: Basic Concepts (1 week)
- Historical development of periodic table
- Modern periodic law and structure
- Basic periodic trends
π Phase 2: Advanced Trends (2 weeks)
- Detailed understanding of each trend
- Exceptions and their explanations
- Numerical problems and calculations
π Phase 3: Practice and Application (1 week)
- Previous year questions
- Comparative analysis
- Speed and accuracy improvement
2. Practice Schedule
π
Daily Practice:
- Basic trend questions: 5-6
- Exception-based questions: 2-3
- Numerical problems: 2-3
- Comparative analysis: 3-4
π Weekly Targets:
- Total questions: 60-70
- Accuracy: 75%
- Time management: 2 hours
- Concept revision: All topics
π‘ Success Tips
1. Memory Techniques
π§ͺ Mnemonics for Trends:
- "LARS": Left to Right, Atomic Radius Smaller
- "LIEN": Left to Right, Ionization Energy Increases
- "LEAN": Left to Right, Electronegativity ANd Nuclear charge increase
π Visual Aids:
- Periodic table color coding
- Trend graphs and charts
- Electronic configuration diagrams
2. Problem-Solving Strategy
π― Step-by-Step Approach:
1. Identify the elements involved
2. Determine their positions in periodic table
3. Recall relevant trends and exceptions
4. Consider electronic configuration
5. Apply the trend with modifications
6. Verify with known examples
π Key Takeaways
1. Essential Concepts
β
Must Know:
- Periodic trends and their explanations
- Exceptions to trends and their causes
- Effective nuclear charge calculations
- Electronic configuration patterns
- Diagonal relationships
β
Must Practice:
- Trend comparisons
- Exception identification
- Numerical calculations
- Periodic table navigation
2. Exam Strategy
π― During Exam:
- Read questions carefully
- Identify elements and their positions
- Check for exceptions before applying trends
- Use process of elimination
- Manage time effectively
π Success Metrics:
- Accuracy: >75%
- Speed: <2 minutes/question
- Concept coverage: 100%
- Exception identification: 90%
Master Classification of Elements and Periodicity with this comprehensive PYQ compilation! π―
This chapter forms the foundation of Inorganic Chemistry. Strong understanding of periodic trends is essential for success in JEE. π
π Happy Learning and Best of Luck for Your JEE Preparation! π