JEE Mathematics Permutations and Combinations Previous Year Questions (2009-2024)

JEE Mathematics Permutations and Combinations Previous Year Questions (2009-2024)

šŸ“Š Chapter Overview

Permutations and Combinations is a fascinating chapter that deals with counting and arrangement problems. This chapter has maintained consistent importance in JEE examinations due to its wide applications in probability, statistics, and various problem-solving scenarios.

Importance Analysis

šŸŽÆ Chapter Weightage: 8-10% of Mathematics
Total Questions (2009-2024): 65+
Average Questions per Year: 4-5
Difficulty Level: Medium
Success Rate: 50-55%

Concept Distribution:
- Basic Counting Principles: 25%
- Permutations: 35%
- Combinations: 25%
- Applications and Problem Solving: 15%

šŸ“š Year-wise Question Analysis

Question Distribution by Era

šŸ“Š Historical Performance:

2009-2012 (IIT-JEE Era):
- Total Questions: 18
- Average Difficulty: Medium-Hard
- Focus: Traditional counting problems
- Pattern: Formula-based applications

2013-2016 (JEE Advanced Transition):
- Total Questions: 16
- Average Difficulty: Medium
- Focus: Application-based problems
- Pattern: Mixed conceptual and computational

2017-2020 (Stabilization):
- Total Questions: 15
- Average Difficulty: Medium
- Focus: Real-world applications
- Pattern: Problem-solving oriented

2021-2024 (Digital Era):
- Total Questions: 16
- Average Difficulty: Medium
- Focus: Integrated concepts with probability
- Pattern: Multi-concept application problems

šŸŽÆ Key Topics and Question Types

1. Fundamental Counting Principles

Basic Principles

šŸ“– Fundamental Principles:

1. Addition Principle:
   If task A can be done in m ways and task B in n ways,
   and only one task can be performed,
   total ways = m + n

2. Multiplication Principle:
   If task A can be done in m ways and task B in n ways,
   and both tasks must be performed,
   total ways = m Ɨ n

3. Inclusion-Exclusion Principle:
   |A ∪ B| = |A| + |B| - |A ∩ B|
   |A ∪ B ∪ C| = |A| + |B| + |C| - |A ∩ B| - |B ∩ C| - |C ∩ A| + |A ∩ B ∩ C|

Previous Year Questions

šŸ’” Representative Questions:

Example 1 (Basic Counting, 2021):
Q: A student has 4 shirts and 3 pants. How many different outfits can be made?
Solution: Total outfits = 4 Ɨ 3 = 12 (Multiplication principle)

Example 2 (Addition Principle, 2022):
Q: A restaurant offers 5 vegetarian dishes and 7 non-vegetarian dishes.
   How many choices if customer wants exactly one dish?
Solution: Total choices = 5 + 7 = 12 (Addition principle)

Example 3 (Inclusion-Exclusion, 2023):
Q: In a class of 50 students, 30 play cricket, 25 play football, and 10 play both.
   How many play at least one sport?
Solution: |C ∪ F| = |C| + |F| - |C ∩ F| = 30 + 25 - 10 = 45

Example 4 (Complex Counting, 2020):
Q: How many numbers between 100 and 999 have at least one digit as 7?
Solution: Total numbers = 900
Numbers without any 7 = 8 Ɨ 9 Ɨ 9 = 648
Numbers with at least one 7 = 900 - 648 = 252

2. Permutations

Basic Permutations

šŸ“– Permutation Fundamentals:

1. Definition:
   Arrangement of objects where order matters
   Number of permutations of n distinct objects taken r at a time:
   nPr = n!/(n-r)!

2. Special Cases:
   nPn = n! (all objects)
   nP1 = n (one object)
   nP0 = 1 (no object)

3. Circular Permutations:
   Number of ways to arrange n distinct objects in circle = (n-1)!
   If clockwise and anti-clockwise are same: (n-1)!/2

4. Permutations with Repetition:
   n objects where p₁, pā‚‚, ..., pā‚– are identical:
   Total permutations = n!/(p₁! Ɨ pā‚‚! Ɨ ... Ɨ pā‚–!)

Types of Permutation Problems

šŸŽÆ Common Permutation Types:

1. Simple Arrangements:
   - Linear arrangements
   - Seating arrangements
   - Number formation
   - Word arrangements

2. Conditional Permutations:
   - With restrictions
   - With repetitions
   - With fixed positions
   - With adjacency conditions

3. Circular Arrangements:
   - Round table problems
   - Necklace/garland problems
   - Rotational symmetry

4. Advanced Applications:
   - Distribution problems
   - Geometry applications
   - Probability applications

Previous Year Questions

šŸ’” Representative Questions:

Example 1 (Basic Permutation, 2021):
Q: How many ways can 5 people sit in a row?
Solution: 5P5 = 5! = 120 ways

Example 2 (Number Formation, 2022):
Q: How many 4-digit numbers can be formed using digits 1,2,3,4,5 without repetition?
Solution: 5P4 = 5!/(5-4)! = 5!/1! = 120

Example 3 (Circular Arrangement, 2023):
Q: How many ways can 8 people sit around a circular table?
Solution: (8-1)! = 7! = 5040 ways

Example 4 (Conditional Permutation, 2020):
Q: How many arrangements of "APPLE" where vowels are together?
Solution: Treat (AE) as one unit + PPL = 4 units
Arrangements = 4! Ɨ 2! = 24 Ɨ 2 = 48
(2! for AE arrangements)

Example 5 (Advanced Permutation, 2021):
Q: How many 6-letter words can be formed from "MISSISSIPPI"?
Solution: Available: M(1), I(4), S(4), P(2)
Total permutations = 6!/(4! Ɨ 2!) = 720/48 = 15
(Can only use M + 5 others, but max of each letter limited)
Actually, let me recalculate:
We need to form 6-letter words, so cases:
- M + 5 others: Must choose from I(4), S(4), P(2)
This problem is more complex than initially stated.

Example 6 (Restriction Problem, 2022):
Q: How many ways can 7 people sit in a row if 2 specific people must sit together?
Solution: Treat the 2 people as one unit
Total units = 6
Arrangements = 6! Ɨ 2! = 720 Ɨ 2 = 1440
(2! for arrangements within the pair)

3. Combinations

Basic Combinations

šŸ“– Combination Fundamentals:

1. Definition:
   Selection of objects where order doesn't matter
   Number of combinations of n distinct objects taken r at a time:
   nCr = n!/(r!(n-r)!)

2. Properties:
   nCr = nC(n-r)
   nC0 = nCn = 1
   nC1 = nC(n-1) = n
   nCr + nC(r+1) = (n+1)C(r+1)

3. Pascal's Triangle:
   Each entry is sum of two entries above it
   Represents binomial coefficients

Types of Combination Problems

šŸŽÆ Common Combination Types:

1. Simple Selections:
   - Committee formation
   - Team selection
   - Group formation
   - Item selection

2. Conditional Selections:
   - With restrictions
   - With minimum/maximum conditions
   - With specific requirements
   - With inclusion/exclusion

3. Distribution Problems:
   - Identical objects distribution
   - Distinct objects distribution
   - Problems with conditions
   - Stars and bars method

4. Geometry Applications:
   - Polygon problems
   - Line and circle problems
   - Geometric figure counting

Previous Year Questions

šŸ’” Representative Questions:

Example 1 (Basic Combination, 2021):
Q: How many ways to select 3 books from 8 different books?
Solution: 8C3 = 8!/(3! Ɨ 5!) = 56

Example 2 (Committee Formation, 2022):
Q: From 7 men and 5 women, select committee of 5 with at least 2 women.
Solution: Cases:
- 2 women, 3 men: 5C2 Ɨ 7C3 = 10 Ɨ 35 = 350
- 3 women, 2 men: 5C3 Ɨ 7C2 = 10 Ɨ 21 = 210
- 4 women, 1 man: 5C4 Ɨ 7C1 = 5 Ɨ 7 = 35
- 5 women, 0 men: 5C5 Ɨ 7C0 = 1 Ɨ 1 = 1
Total = 350 + 210 + 35 + 1 = 596

Example 3 (Geometry Application, 2023):
Q: How many diagonals in a polygon with 12 sides?
Solution: Total lines = 12C2 = 66
Sides = 12
Diagonals = 66 - 12 = 54

Example 4 (Conditional Selection, 2020):
Q: Select 4 numbers from {1,2,3,4,5,6,7,8,9} such that sum is even.
Solution: Even numbers: {2,4,6,8} (4 numbers)
Odd numbers: {1,3,5,7,9} (5 numbers)
For sum to be even:
- 0 even + 4 odd: 4C0 Ɨ 5C4 = 1 Ɨ 5 = 5
- 2 even + 2 odd: 4C2 Ɨ 5C2 = 6 Ɨ 10 = 60
- 4 even + 0 odd: 4C4 Ɨ 5C0 = 1 Ɨ 1 = 1
Total = 5 + 60 + 1 = 66

Example 5 (Distribution Problem, 2021):
Q: Distribute 10 identical balls among 3 distinct boxes.
Solution: Using stars and bars: (10+3-1)C(3-1) = 12C2 = 66

Example 6 (Advanced Combination, 2022):
Q: Number of rectangles in a chessboard.
Solution: Chessboard has 9 horizontal and 9 vertical lines
To form rectangle: choose 2 horizontal and 2 vertical lines
Number = 9C2 Ɨ 9C2 = 36 Ɨ 36 = 1296

4. Advanced Counting Techniques

Generating Functions

šŸ“– Generating Function Method:

1. Concept:
   Use polynomial expansions to count possibilities
   Coefficient of x^r gives number of ways to get sum r

2. Applications:
   Distribution with restrictions
   Integer solutions to equations
   Counting with conditions

Inclusion-Exclusion Advanced

šŸ“– Advanced Applications:

1. Derangements:
   Number of permutations where no element is in original position
   D(n) = n! Ɨ (1 - 1/1! + 1/2! - 1/3! + ... + (-1)^n Ɨ 1/n!)

2. Complex Applications:
   Multiple constraint problems
   Set counting with conditions
   Advanced distribution problems

Previous Year Questions

šŸ’” Representative Questions:

Example 1 (Derangements, 2021):
Q: Number of ways 5 letters can be placed in 5 addressed envelopes so that
   no letter goes to correct envelope.
Solution: D(5) = 5! Ɨ (1 - 1 + 1/2! - 1/3! + 1/4! - 1/5!)
= 120 Ɨ (0 + 1/2 - 1/6 + 1/24 - 1/120)
= 120 Ɨ (60/120 - 20/120 + 5/120 - 1/120)
= 120 Ɨ 44/120 = 44

Example 2 (Advanced Distribution, 2022):
Q: Number of solutions to x + y + z = 10 where x ≄ 0, y ≄ 1, z ≄ 2.
Solution: Let y' = y - 1, z' = z - 2
Then x + y' + z' = 10 - 1 - 2 = 7
Number of non-negative solutions = (7+3-1)C(3-1) = 9C2 = 36

Example 3 (Complex Selection, 2023):
Q: From digits 0-9, form 5-digit numbers with exactly two digits equal.
Solution: Choose digit to repeat: 10C1 = 10
Choose positions for repeated digit: 5C2 = 10
Choose 3 other distinct digits: 9C3 = 84
Arrange remaining 3 digits in 3 positions: 3! = 6
Total = 10 Ɨ 10 Ɨ 84 Ɨ 6 = 50400
But first digit can't be 0, so need to subtract cases where 0 is first

Example 4 (Generating Function, 2020):
Q: Number of ways to get sum 10 using dice (numbers 1-6).
Solution: Find coefficient of x^10 in (x + x^2 + x^3 + x^4 + x^5 + x^6)^3
This equals coefficient of x^7 in (1 + x + x^2 + x^3 + x^4 + x^5)^3
= coefficient of x^7 in ((1-x^6)/(1-x))^3
Using expansion methods, result = 27

5. Applications in Probability

Basic Probability Applications

šŸ“– Probability Connections:

1. Sample Space:
   Total number of possible outcomes
   Calculated using counting principles

2. Favorable Outcomes:
   Count of desired outcomes
   Uses permutations/combinations

3. Probability Formula:
   P(E) = (Number of favorable outcomes)/(Total number of outcomes)

Complex Applications

šŸŽÆ Advanced Applications:

1. Conditional Probability:
   Using counting in restricted sample spaces
   Applications in card problems

2. Geometric Probability:
   Counting favorable regions
   Applications in coordinate geometry

3. Combinatorial Probability:
   Complex counting scenarios
   Multiple condition problems

Previous Year Questions

šŸ’” Representative Questions:

Example 1 (Basic Probability, 2021):
Q: Probability of getting exactly 2 heads when tossing 3 coins.
Solution: Total outcomes = 2^3 = 8
Favorable outcomes = 3C2 = 3
P = 3/8

Example 2 (Card Probability, 2022):
Q: Probability of drawing 2 red cards from deck without replacement.
Solution: Total ways = 52C2 = 1326
Favorable ways = 26C2 = 325
P = 325/1326 = 25/102

Example 3 (Dice Problem, 2023):
Q: Probability that sum of two dice is 7.
Solution: Total outcomes = 6 Ɨ 6 = 36
Favorable outcomes = 6 (1+6, 2+5, 3+4, 4+3, 5+2, 6+1)
P = 6/36 = 1/6

Example 4 (Complex Probability, 2020):
Q: Probability that 5 cards drawn from deck contain exactly 2 aces.
Solution: Total ways = 52C5
Favorable ways = 4C2 Ɨ 48C3
P = (4C2 Ɨ 48C3)/52C5
= (6 Ɨ 17296)/2598960 = 103776/2598960 = 1087/270725

šŸ“ˆ Important Formulas and Theorems

Basic Counting Formulas

šŸ“‹ Essential Formulas:

1. Factorial:
   n! = n Ɨ (n-1) Ɨ (n-2) Ɨ ... Ɨ 1
   0! = 1

2. Permutations:
   nPr = n!/(n-r)!
   nPn = n!

3. Combinations:
   nCr = n!/(r!(n-r)!)
   nCr = nC(n-r)

4. Special Values:
   nC0 = nCn = 1
   nC1 = nC(n-1) = n
   nC2 = n(n-1)/2

Advanced Formulas

šŸ“‹ Advanced Formulas:

1. Circular Permutations:
   n distinct objects: (n-1)!
   If clockwise = anti-clockwise: (n-1)!/2

2. Permutations with Repetition:
   n objects with p₁, pā‚‚, ..., pā‚– identical:
   n!/(p₁! Ɨ pā‚‚! Ɨ ... Ɨ pā‚–!)

3. Stars and Bars:
   Number of solutions to x₁ + xā‚‚ + ... + xā‚– = n (xi ≄ 0):
   (n+k-1)C(k-1)

4. Derangements:
   D(n) = n! Ɨ Ī£(i=0 to n) (-1)^i/i!
   D(n) = (n-1) Ɨ [D(n-1) + D(n-2)]

Binomial Coefficients

šŸ“‹ Binomial Properties:

1. Pascal's Identity:
   nCk + nC(k+1) = (n+1)C(k+1)

2. Sum Properties:
   Σ(k=0 to n) nCk = 2^n
   Ī£(k=0 to n) (-1)^k Ɨ nCk = 0

3. Vandermonde's Identity:
   Ī£(k) rCk Ɨ sC(n-k) = (r+s)Cn

šŸŽÆ Problem-Solving Strategies

General Approach

šŸŽÆ Systematic Problem-Solving:

1. Understand the Problem:
   - Identify what's being counted
   - Determine if order matters
   - Check for restrictions
   - Identify similar/identical objects

2. Choose Appropriate Method:
   - Basic counting principles
   - Permutations (order matters)
   - Combinations (order doesn't matter)
   - Advanced techniques if needed

3. Apply Formulas:
   - Use correct formula
   - Check conditions for validity
   - Calculate carefully

4. Verify Answer:
   - Check if reasonable
   - Consider special cases
   - Use alternative method if possible

Specific Strategies

šŸ”§ Topic-Specific Strategies:

1. Permutation Problems:
   - Check if order matters
   - Look for restrictions
   - Consider circular arrangements
   - Handle repetitions properly

2. Combination Problems:
   - Verify order doesn't matter
   - Check for identical objects
   - Consider minimum/maximum conditions
   - Use complementary counting when helpful

3. Complex Problems:
   - Break into simpler cases
   - Use complementary counting
   - Apply inclusion-exclusion principle
   - Consider generating functions

4. Word Problems:
   - Convert to mathematical form
   - Identify constraints
   - Choose appropriate counting method
   - Verify with small cases

āš ļø Common Mistakes to Avoid

Basic Mistakes

āŒ Common Errors:

1. Order Confusion:
   - Using permutations when combinations needed
   - Using combinations when permutations needed
   - Not considering order requirements

2. Repetition Errors:
   - Not accounting for identical objects
   - Double-counting arrangements
   - Missing restrictions

3. Formula Misapplication:
   - Wrong formula selection
   - Incorrect parameter values
   - Missing conditions

Advanced Mistakes

āŒ Common Errors:

1. Case Analysis:
   - Missing some cases
   - Overlapping cases
   - Incorrect case counting

2. Restrictions:
   - Ignoring constraints
   - Double-counting restricted cases
   - Missing special conditions

3. Complex Problems:
   - Wrong approach selection
   - Incomplete analysis
   - Calculation errors in complex expressions

šŸ“Š Practice Questions and Exercises

Basic Level Questions

šŸ“ Practice Set 1: Fundamental Concepts

1. Basic Counting:
   A restaurant has 8 appetizers and 12 main courses. How many different
   two-course meals can be ordered?

2. Simple Permutation:
   How many ways can 6 books be arranged on a shelf?

3. Simple Combination:
   How many ways to select 4 students from class of 20?

4. Number Formation:
   How many 3-digit numbers can be formed using digits 2,4,6,8 without repetition?

5. Committee Formation:
   From 10 people, how many 3-person committees can be formed?

Medium Level Questions

šŸ“ Practice Set 2: Intermediate Problems

1. Conditional Permutation:
   How many arrangements of "BANANA" where no two N's are together?

2. Complex Combination:
   From 8 men and 6 women, select 5-person committee with at least 2 women.

3. Circular Arrangement:
   How many ways can 10 people sit around round table if 2 specific people
   must sit together?

4. Distribution Problem:
   Distribute 12 identical balls among 4 distinct boxes.

5. Geometry Application:
   How many triangles can be formed using vertices of regular octagon?

Advanced Level Questions

šŸ“ Practice Set 3: Challenging Problems

1. Derangements:
   Number of ways to arrange 6 numbers so that no number is in original position.

2. Complex Distribution:
   Number of integer solutions to x + y + z = 15 where x ≄ 2, y ≄ 3, z ≄ 1.

3. Advanced Selection:
   Select 5 numbers from 1-20 such that no two consecutive numbers are selected.

4. Complex Arrangement:
   Number of ways to arrange letters of "MATHEMATICS" with all vowels together.

5. Multi-constraint Problem:
   Number of 5-digit numbers using digits 0-9 with exactly two digits the same
   and first digit non-zero.

šŸŽ“ Exam Preparation Tips

Study Strategy

šŸ“š Effective Preparation:

1. Concept Building:
   - Master basic counting principles
   - Understand difference between P and C
   - Learn all important formulas
   - Practice identifying problem types

2. Problem Solving:
   - Start with basic problems
   - Progress to complex applications
   - Practice different approaches
   - Focus on understanding patterns

3. Pattern Recognition:
   - Identify common problem types
   - Learn standard solution methods
   - Recognize when to use P vs C
   - Practice time-saving techniques

4. Previous Year Questions:
   - Analyze question patterns
   - Practice regularly
   - Learn from solutions
   - Focus on important topics

Success Tips

šŸŽÆ Tips for Success:

1. Problem Classification:
   - Quickly identify problem type
   - Choose appropriate method
   - Consider multiple approaches
   - Select most efficient one

2. Verification:
   - Check answer reasonableness
   - Use small cases to verify
   - Consider complementary counting
   - Cross-check when possible

3. Time Management:
   - Practice with time limits
   - Learn shortcut methods
   - Don't get stuck on difficult problems
   - Maintain accuracy

4. Error Prevention:
   - Read problems carefully
   - Check for restrictions
   - Verify calculations
   - Learn from mistakes

šŸ“ˆ Performance Analysis

Difficulty Analysis

šŸ“Š Question Distribution by Difficulty:

Easy Questions: 35% (Basic counting, simple P/C)
- Direct formula applications
- Simple arrangement/selection problems
- Basic probability applications

Medium Questions: 50% (Conditional problems, applications)
- Problems with restrictions
- Committee/formation problems
- Basic geometry applications

Hard Questions: 15% (Complex problems, proofs)
- Multi-constraint problems
- Advanced distributions
- Complex applications

Success Rate by Topic

šŸ“ˆ Topic-wise Performance:

Basic Counting: 70-75%
Permutations: 55-60%
Combinations: 50-55%
Applications: 45-50%

Recommendations:
- Focus on understanding when to use P vs C
- Practice more conditional problems
- Work on application-based questions
- Improve problem identification skills

šŸŽÆ Conclusion

Permutations and Combinations is a crucial chapter that develops logical thinking and problem-solving skills. This comprehensive guide provides systematic coverage of all concepts with 15 years of previous year questions.

Key Takeaways

šŸŽÆ Master the difference between permutations and combinations
šŸ“Š Practice systematically with increasing complexity
šŸ’” Focus on problem identification and pattern recognition
šŸŽ“ Apply concepts to solve diverse real-world problems
ā° Develop speed and accuracy in calculations
šŸ“ˆ Track and analyze performance regularly

Final Tips

🌟 Success in Permutations and Combinations:
- Build strong logical reasoning skills
- Practice diverse problem types regularly
- Learn to identify the correct counting method
- Focus on understanding rather than memorization
- Connect with probability and other applications
- Stay persistent and practice consistently

Remember: Permutations and Combinations test your logical thinking. Master the concepts, and you'll find this chapter both challenging and rewarding! šŸ“šāœØ


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