PYQ NEET- Chemical Kinetics L-4

Question: For a chemical reaction#

$$ 4 \mathrm{~A}+3 \mathrm{~B} \rightarrow 6 \mathrm{C}+9 \mathrm{D} $$

Rate of formation of $C$ is $6 \times 10^{-2} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}$ and rate of disappearance of A is $4 \times 10^{-2} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}$. The rate of reaction and amount of $B$ consumed in interval of 10 seconds, respectively will be :

A) $10 \times 10^{-2} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}$ and $30 \times 10^{-2} \mathrm{~mol} \mathrm{~L}^{-1}$

B) $1 \times 10^{-2} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}$ and $30 \times 10^{-2} \mathrm{~mol} \mathrm{~L}^{-1}$

C) $10 \times 10^{-2} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}$ and $10 \times 10^{-2} \mathrm{~mol} \mathrm{~L}^{-1}$

D) $1 \times 10^{-2} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}$ and $10 \times 10^{-2} \mathrm{~mol} \mathrm{~L}^{-1}$

Answer: $1 \times 10^{-2} \mathrm{~mol} \mathrm{~L}^{-1} \mathrm{~s}^{-1}$ and $30 \times 10^{-2} \mathrm{~mol} \mathrm{~L}^{-1}$#