PYQ NEET- Current Electricity L-6

Question: 10 resistors, each of resistance $\mathrm{R}$ are connected in series to a battery of emf $E$ and negligible internal resistance. Then those are connected in parallel to the same battery, the current is increased $n$ times. The value of $n$ is : (2023)#

A) 100

B) 1

C) 1000

D) 10

Answer: 100#

Explanation#

$\mathrm{I}_{\mathrm{S}}=\frac{E}{10 R} \ldots \ldots(1)$

$\mathrm{I}_{\mathrm{P}}=\frac{\mathrm{E}}{\mathrm{R} / 10}=\frac{10 \mathrm{E}}{\mathrm{R}} \ldots .(2)$

$\mathrm{n}=\frac{\mathrm{I}{\mathrm{P}}}{\mathrm{I}{\mathrm{S}}}=100 \Rightarrow \mathrm{n}=100$