PYQ NEET- Electromagnetic Waves L-1

Question: In a plane electromagnetic wave travelling in free space, the electric field component oscillates sinusoidally at a frequency of $2.0 \times 10^{10} \mathrm{~Hz}$ and amplitude $48 \mathrm{Vm}^{-1}$. Then the amplitude of oscillating magnetic field is : (Speed of light in free space $=3 \times 10^8 \mathrm{~m} \mathrm{~s}^{-1}$ ): (NEET-2023)#

A) $1.6 \times 10^{-8} \mathrm{~T}$

B) $1.6 \times 10^{-7} \mathrm{~T}$

C) $1.6 \times 10^{-6} \mathrm{~T}$

D) $1.6 \times 10^{-9} \mathrm{~T}$

Answer: $1.6 \times 10^{-7} \mathrm{~T}$#

Explanation#

$C=\frac{E_0}{B_0} $

$\mathrm{~B}_0=\frac{\mathrm{E}_0}{\mathrm{C}}$

$=\frac{48}{3 \times 10^8}$

$=1.6 \times 10^{-7} \mathrm{~T}$