Previous Year NEET Question- Gravitation L-8

Question: A particle of mass ’ $\mathrm{m}$ ’ is projected with a velocity $v=\mathrm{kV}{\mathrm{e}}=(\mathrm{k}<1)$ from the surface of the earth. $\left(\mathrm{V}{\mathrm{e}}=\right.$ escape velocity $)$#

The maximum height above the surface reached by the particle is :

A) $\frac{R k^2}{1-k^2}$

B) $R\left(\frac{k}{1-k^2}\right)^2$

C) $R\left(\frac{k}{1+k^2}\right)^2$

D) $\frac{R^2 k}{1+k}$

Answer: $\frac{R k^2}{1-k^2}$#