PYQ NEET- Moving Charges And Magnetism L-7

In an ammeter $99.8 %$ of main current passes through the galvanometer. If resistance of galvanometer is $\mathrm{G}$, the resistance of ammeter will be#

A) $\frac{1}{499} G$

B) $\frac{499}{500} G$

C) $\frac{1}{500} G$

D) $\frac{500}{499} G$

Answer: (C) $\frac{1}{500} G$#

Sol:#

In parallel arrangement, I $\alpha$ R$^{-1}$

Now G/S $=99.8 / 0.2$ $$ S=G / 499.0 $$

Hence, $R_A=\frac{G S}{G+S}=\frac{G}{G+S}$