PYQ NEET- Moving Charges And Magnetism L-8

A milli voltmeter of 25 millivolt range is to be converted into an ammeter of 25 ampere range. The value (in ohm) of necessary shunt will be

A) 0.001

B) 0.01

1

D) 0.05

Answer: (A) 0.001

Sol:

$$ S=\frac{V_g}{\left(I-I_g\right)} $$

Neglecting $\mathrm{I}_{\mathrm{g}}$ $$ \therefore S=\frac{V_g}{I}=\frac{25 \times 10^{-3} \mathrm{~V}}{25 \mathrm{~A}}=0.001 \Omega $$



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