PYQ NEET- Chemical Equilibrium-1 L-7

Question: Which of the following statements is correct for a reversible process in a state of equilibrium?#

A) $\Delta G^0=-2.30 R T \log K$

B) $\Delta \mathrm{G}^0=2.30 \mathrm{RT} \log \mathrm{K}$

C) $\Delta \mathrm{G}=-2.30 \mathrm{RT} \log \mathrm{K}$

D) $\Delta \mathrm{G}=2.30 \mathrm{RT} \log \mathrm{K}$

Answer: $\Delta G^0=-2.30 R T \log K$#

Solution:#

$$ \Delta \mathrm{G}=\Delta \mathrm{G}^0+2.303 \mathrm{RT} \log \mathrm{Q} $$

At equilibrium, when $\Delta \mathrm{G}=0$ and $\mathrm{Q}=\mathrm{K}$

then $0=\Delta \mathrm{G}^0+2.303 \mathrm{RT} \log \mathrm{K}$

$\Delta \mathrm{G}^{\circ}=-2.303 \mathrm{RT} \log \mathrm{K}$