PYQ NEET- Circuits With Resistance And Inductance

• NEET 2019: A coil of inductance 0.5 H and resistance 100 $\Omega$ is connected to a 220 V, 50 Hz AC supply. The maximum current in the coil is:

(A) 1.1 A (B) 2.2 mA (C) 3.3 mA (D) 4.4 mA

The answer is (A).

The maximum current in the coil is determined by:

$I_{max} = \frac{V_{max}}{\sqrt{R^2 + (2\pi f L)^2}}$

Substituting the values, we get:

$I_{max} = \frac{220}{\sqrt{100^2 + (2\pi * 50 * 0.5)^2}} = 1.1 A$

• NEET 2018: A series LCR circuit with L = 100 mH, C = 10 $\mu$F and R = 100 $\Omega$ is connected to a 220 V AC supply