Previous Year NEET Question- Conic Sections

• 2019:

The equation of an ellipse with center $(h, k)$, major axis $2a$, minor axis $2b$, and eccentricity $e$ is given by $\frac{(x-h)^2}{a^2} + \frac{(y-k)^2}{b^2} = 1$

$$ \frac{(x - h)^2}{a^2} + \frac{(y - k)^2}{b^2} = 1 $$

In this case, we have $h = 0$, $k = 0$, $a = 5$, $b = 3$, and $e = \frac{\sqrt{5^2 - 3^2}}{5}$. Substituting these values into the equation of the ellipse, we get

$$ \frac{(x - 0)^2}{5^2} + \frac{(y - 0)^2}{3^2} = 1 $$

or, equivalently,

$$ \frac{x^2}{25} + \frac{y^2}{9} = 1 $$

• 2018:

The equation of a hyperbola with center $(h, k)$, foci $(h \pm c, k)$,