2018:
The answer is (A) Blv
The induced emf in the rod is given by:
e = Blv
2017:
The answer is (C) Blv2/2
The power dissipated in the rod is given by:
P = I^2R = (Blv)^2/R = Blv2/2
where I is the current flowing through the rod and R is the resistance of the rod.
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