Previous Year NEET Question- Entropy And T-S Diagram

• NEET 2019:

The efficiency of a Carnot engine is given by

η = 1 - Tc/Th

where Tc and Th are the temperatures of the cold and hot reservoirs, respectively.

In this problem, Tc = 600 K and Th = 1000 K. Therefore, the efficiency of the engine is

η = 1 - 600/1000 = 0.4

• NEET 2018:

The efficiency of a Carnot engine is given by

η = 1 - Tc/Th

where Tc and Th are the temperatures of the cold and hot reservoirs, respectively.

In this problem, Tc = 273 + 27 = 300 K and Th = 273 + 227 = 490 K. Therefore, the efficiency of the engine is

η = 1 - 300/490 = 0.36

• **NEET