PYQ NEET- System Of Particles And Rotational Motion
- Question: A particle of mass m is moving with a constant speed v along the perimeter of a circle of radius r. Find the angular momentum of the particle about the centre of the circle.
Answer: The angular momentum of a particle about a point is given by:
$$L = mvr$$
In this case, the particle is moving with a constant speed v, so the angular momentum is constant. The angular momentum is also proportional to the mass of the particle and the radius of the circle.
Explanation: The angular momentum of a particle about a point is a measure of the particle’s rotational inertia. It is a vector quantity, and its direction is perpendicular to the plane of rotation and is in the direction of the particle’s motion. The angular momentum of a particle can be calculated using the following equation:
$$L = mvr$$
where:
- $L$ is the angular momentum of the particle, in units of kilogram-meters squared per second (kg-m2/s)
- $m$ is the mass of the particle, in kilograms (kg)
- $v$ is the velocity of the particle, in meters per second (
BETA
