PYQ NEET- Introduction To Simple Harmonic Motion

• The answer is (B)

• A particle is executing SHM. The time taken for it to go from one extreme position to half of the amplitude is T1. The time taken to go from one extreme position to the other extreme position is T2. The ratio of T1 to T2 is (A) 1/√2 (B) √2 (C) 1/2 (D) 2

The formula for the time period of a particle executing SHM is: $ T = 2\pi \sqrt{\frac{m}{k}} $

T = 2π√(m/k)

where m is the mass of the particle and k is the spring constant.

In this problem, we are given that the time taken for the particle to go from one extreme position to half of the amplitude is T1. We can find the time period of the oscillation by using the equation: T = 4T1 + (π/ω)

T1 = 2π√(m/k)

The time taken for the particle to go from one extreme position to the other extreme position is T/2. We can find the time period of the oscillation by using the equation:

T2 = 2π√(k/m)

The ratio of T1 relaxation time