PYQ NEET- Firchhoffs Laws Current And Electricity

1. In the given circuit, the current flowing through 10$\Omega$ resistor is : (A) 0.1A (B) 0.2A (C) 0.3A (D) 0.4A (NEET 2019)

Answer: (C)

Explanation:

The equivalent resistance between the two parallel resistors is:

$$\frac{1}{R_{eq}} = \frac{1}{10} + \frac{1}{10} = \frac{2}{10}$$

So, the total resistance in the circuit is:

$$R = \frac{10}{2} = 5\Omega$$

Therefore, the current flowing through the 10$\Omega$ resistor is:

$$I = \frac{V}{R} = \frac{6}{5} = 1.2A$$

2. The equivalent resistance between A and B in the given circuit is : (NEET 2019)

Answer: 3$\Omega$

Explanation: