Previous Year NEET Question- Logarithm Lecture

2 2. Find the sum of all natural numbers between 100 and 200, which are divisible by 7.

(A) 1320 (B) 1280 (C) 1200 (D) 1300

The answer is: (C)

A step-by-step solution:

Number of multiples of 7 between 100 and 200 = (196 - 105)/7 + 1 = 14 Sum of these numbers = 7*10 = 70 100 is not divisible by 7, but 200 is not. So, the answer is 70 - 100 = -30.



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