PYQ NEET- Problem Solving Simple Harmonic Motion

What is the angular frequency of a particle executing simple harmonic motion with a period of 2.0 s?

• Answer: The answer is $\frac{\pi}{2}$ rad/s.

• Explanation: The period of a simple harmonic motion is the time it takes for the particle to complete one oscillation. The angular velocity of a particle executing simple harmonic motion is given by $\omega = \frac{2\pi}{T}$, where $T$ is the period of the oscillation. In this case, the period is 2.0 s, so the angular velocity is $\omega = \frac{2\pi}{2.0\ \mathrm{s}} = \frac{\pi}{2}$ rad/s.

•                     * **Question:** A particle is executing simple harmonic motion with an amplitude of 2.0 m. If the maximum speed of the particle is 10.0 m/s, what is the angular frequency of the oscillation?
  

• Answer: The answer is 5.0 rad/s.

• Explanation: The maximum speed of a particle executing simple harmonic motion is given by