PYQ NEET- Problems On Trig And Inv Trig Functions
- 2019: Question 1: Find the value of $\tan^{-1} \left( \frac{1}{2} \right) + \tan^{-1} \left( \frac{1}{3} \right)$.
The answer is $\frac{\pi}{4}$.
We can use the following identity to solve this problem:
$\tan^{-1} x + \tan^{-1} y = \tan^{-1} \left( \frac{x + y}{1 - xy} \right)$
In this case, we have $x = \frac{1}{2}$ and $y = \frac{1}{3}$. Substituting these values into the identity, we get:
$\tan^{-1} \left( \frac{1}{2} \right) + \tan^{-1} \left( \frac{1}{3} \right) = \tan^{-1} \left( \frac{\frac{1}{2} + \frac{1}{3}}{1 - \left( \frac{1}{2} \right) \left( \frac{1}{3
BETA
