PYQ NEET- Series And Parallel Combinations Of Cells

2019:

The answer is (A) 1 A.

The current through the 10 ohm resistor is calculated using Ohm’s Law.

I = \frac{10}{10} = 1 A

2018:

The answer is (C) 1 Ω.

The equivalent resistance between A and B is given by:

R = \frac{1}{1} + \frac{1}{1} = 2 Ω

2017:

The answer is (A) 1 A.

The current through the 10 Ω resistor is given by:

I = \frac{12}{10} = 1.2 A

2016:

The answer is (C) 2 A.

The current through the 10 ohm resistor is given by:

I = \frac{10}{5} = 2 A