Previous Year NEET Question- Wave Optics L-1

The frequency of a light wave in a material is $2 \times 10^{14} \mathrm{~Hz}$ and wavelength is $5000 \AA$. The refractive index of material will be

A) 1.50

B) 3.00

C) 1.33

D) 1.40

Answer: 3.00

Sol:

$\mu=\frac{\text { velocity of light in vacuum }(c)}{\text { velocity of light in medium }(v)}$ $$ \begin{alignedat} & \therefore \quad v=f \lambda=2 \times 10^{14} \times 5000 \times 10^{-10}=10^8 \mathrm{~m} / \mathrm{s} \ & \therefore \quad \mu=\frac{c}{v_{\text {med }}}=\frac{3 \times 10^8}{2 \times 10^8}=1.5 \end{aligned} $$



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