Related Problems with Solutions

Problem 3 : Consider a chemical reaction with ∆H = -200 kJ/mol and ∆S = -400 J/(mol•K). Determine the temperature at which this reaction becomes spontaneous.#

Solution :#

To determine the temperature (T) at which the reaction becomes spontaneous, you can use the equation:

∆G = ∆H - T∆S

At the point where the reaction becomes spontaneous, ∆G will be zero. So, we have:

0 = -200 kJ/mol - T * (-400 J/(mol•K))

Solving for T:

T = (-200000 J/mol) / (-400 J/(mol•K)) = 500 K

So, the reaction becomes spontaneous at 500 K.