Capacitive Circuitsalternating Currents Topic

NEET

  1. Capacitor
  • Capacitive reactance: $$X_C=\frac{1}{2\pi fC}$$
  • Current flowing: $$I=\frac{V}{X_C}$$

$$X_C= \frac{1}{2\pi \times 50 \text{ Hz} \times 100\times 10^{-6} \text{ F}}=318.31\Omega$$

$$I=\frac{200\text{ V}}{318.31\Omega}=\boxed{0.628 \text{ A}}$$

  1. AC Circuit with Inductor and Capacitor:
  • Impedance: $$Z=\sqrt{R^2+(X_L-X_C)^2}$$
  • Current flowing: $$I=\frac{V}{Z}$$

$$X_L=2\pi f L=2\pi \times 50\text{ Hz}\times 0.1\text{ H}=31.42 \Omega$$

$$Z=\sqrt{10^2+(31.42-318.31)^2}=\boxed{300.85 \Omega}$$

$$I=\frac{200\text{ V}}{300.85\Omega}=\boxed{0.665 \text{ A}}$$

  1. Step-up Transformer:
  • Voltage across secondary: $$V_s=\frac{N_s}{N_p}V_p$$

$$V_s=\frac{200\ \text{ turns}}{100\text{ turns}}\times100\text{ V}=\boxed{200\text{ V}}$$


CBSE Board Exams


  1. Capacitor
  • Capacitive reactance: $$X_C=\frac{1}{2\pi fC}$$

  • Current flowing: $$I=\frac{V}{X_C}$$ $$X_C=\frac{1}{2\pi\times 50 \text{ Hz}\times 100\times10^{-6}\text{ F}}=\boxed{318.31 \Omega}$$

$$I=\frac{200\text{ V}}{318.31\Omega}=\boxed{0.628\text{ A}}$$

  1. AC Circuit with Inductor and Capacitor
  • Impedance: $$Z=\sqrt{R^2+(X_L-X_C)^2}$$

  • Current flowing: $$I=\frac{V}{Z}$$

$$X_L=2\pi fL=2\pi\times50\text{ Hz}\times0.1\text{ H}=31.42\Omega$$

$$Z=\sqrt{10^2+(31.42-318.31)^2}=\boxed{300.85\Omega}$$

$$I=\frac{200\text{ V}}{300.85\Omega}=\boxed{0.665\text{ A}}$$

  1. Step-up Transformer:
  • Voltage across secondary: $$V_s=\frac{N_s}{N_p}V_p$$

$$V_s=\frac{200\text{ turns}}{100\text{ turns}}\times100\text{ V}=\boxed{200\text{ V}}$$

  1. AC Generator:
  • Peak voltage: $$V_{peak}=V_{rms}\sqrt{2}$$ $$V_{peak}=220 \text{ V}\times \sqrt{2}=\boxed{311\text{ V}}$$

  • Peak current: $$I_{peak}=\frac{V_{peak}}{R}$$ $$I_{peak}=\frac{311 \text{ V}}{100 \Omega}=\boxed{3.11\text{ A}}$$

  1. Inductor with AC Source:
  • $$I_{rms}=\frac{V_{rms}}{Z}, where Z=\sqrt{R^2+X_L^2}$$

$$X_L=2\pi fL=2\pi (60\text{ Hz})(0.1\text{ H})=37.7\Omega$$

$$Z=\sqrt{10^2+37.7^2}=38.6 \Omega$$

  • Current amplitude: $$I_{rms}=\frac{120\text{ V}}{38.6 \Omega}=\boxed{3.11 \text{ A}}$$
  1. Capacitor with AC Source:

With $$X_C=\frac{1}{2\pi fC}=26.52 \Omega$$

  • Current amplitude: $$I=V_{rms} \frac{1}{X_C}=\frac{120\text{ V}}{26.52\Omega}=\boxed{4.52 \text{ A}}$$


sathee Ask SATHEE

Welcome to SATHEE !
Select from 'Menu' to explore our services, or ask SATHEE to get started. Let's embark on this journey of growth together! 🌐📚🚀🎓

I'm relatively new and can sometimes make mistakes.
If you notice any error, such as an incorrect solution, please use the thumbs down icon to aid my learning.
To begin your journey now, click on

Please select your preferred language