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Shortcut Methods

I. Kinematics

1. Uniform Circular Motion: To find the tangential velocity (v) of a point on the rim of a rotating disk, simply multiply the angular velocity (\omega) by the radius (r) of the disk.

$$v = \omega r$$


2. Uniform Angular Acceleration: To find the angular displacement (\theta) of a rotating wheel that starts from rest and accelerates uniformly, use the following formula:

$$ \theta = \frac{1}{2} \alpha t^2 $$

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Shortcut Methods

1. Sum of n terms of an A.P.

$$S_n = \frac{n}{2}[2a_1 + (n - 1)d]$$

where (a_1) is the first term, (d) is the common difference, and (n) is the number of terms.

2. Sum of n terms of a G.P.

$$S_n = \frac{a_1(r^n - 1)}{r - 1}$$

where (a_1) is the first term, (r) is the common ratio, and (n) is the number of terms.

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  1. Determine the number of neutrons in an atom of carbon-14 given that its atomic number is 6 and mass number is 14.
  • Solution:
    • The number of neutrons = mass number - atomic number
    • = 14 - 6
    • = 8 neutrons
  1. Calculate the binding energy per nucleon of oxygen-16, given its mass defect is 0.138 atomic mass units (amu).
  • Solution:
    • Binding energy per nucleon = (Mass defect/Mass number)
    • = (0.138 amu / 16 amu)
    • = 0.008625 amu/nucleon
  1. A sample of a radioactive substance has a half-life of 10 days. If the initial activity of the sample is 100 decays per minute, what will be its activity after 20 days?
  • Solution:
    • After 1 half-life (10 days), the activity will be 100/2 = 50 decays per minute.
    • After another 10 days (20 days total), the activity will be 50/2 = 25 decays per minute.

CBSE Board Exam - Numerical Problems.


  1. An atom has 17 protons and 18 neutrons. What is its atomic number and mass number?
  • Solution:
    • Atomic number = number of protons = 17
    • Mass number = number of protons + number of neutrons = 17 + 18 = 35
  1. Calculate the relative atomic mass of an element if it has two isotopes with masses 20 amu and 22 amu, and the respective abundances are 90% and 10%.
  • Solution:
    • Relative atomic mass = (mass of isotope 1 x abundance of isotope 1) + (mass of isotope 2 x abundance of isotope 2)
    • = (20 amu x 0.90) + (22 amu x 0.10)
    • = 20.2 amu
  1. A radioactive element has a half-life of 5 hours. If 1000 atoms are present initially, how many atoms will remain after 10 hours?
  • Solution:
    • After 1 half-life (5 hours), 1000/2 = 500 atoms will remain.
    • After another 5 hours (10 hours total), 500/2 = 250 atoms will remain.

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Shortcut Methods

Shortcuts and Tricks for Electrostatic Problems:

  • Use symmetry to simplify the problem. Often, the charge distribution or geometry of a problem has some symmetry that can be exploited to simplify the calculation. For example, if the charge distribution is spherically symmetric, then the electric field will be the same in all directions.
  • Use Gauss’s law to calculate the electric flux through a closed surface. Gauss’s law can be used to calculate the net electric flux through a closed surface without having to know the details of the charge distribution inside the surface. This can be a powerful tool for solving problems involving complex charge distributions.
  • Use the method of images to solve problems involving conductors and dielectrics. The method of images involves placing imaginary charges in the problem in such a way that the boundary conditions are satisfied. This can be a powerful tool for solving problems involving the interaction of electric fields with conductors and dielectrics.
  • Use superposition to combine the effects of multiple charges. The principle of superposition states that the net electric field due to a collection of charges is the vector sum of the electric fields due to each individual charge. This can be a useful tool for solving problems involving multiple charges.
  • Use energy conservation to solve problems involving the motion of charged particles. Energy conservation can be used to determine the velocity and trajectory of charged particles in electric fields. This can be a useful tool for solving problems involving the motion of charged particles in accelerators, ion thrusters, and other devices.

CBSE Board Level


Shortcuts and Tricks for Electrostatic Problems:

  • Remember the formulas for the electric field due to a point charge and a dipole. These formulas are: $$E = \frac{kq}{r^2}$$ for a point charge and $$E = \frac{1}{4\pi\epsilon_0}\frac{2qs}{r^3}$$ for a dipole.
  • Use Gauss’s law to calculate the electric flux through a closed surface. Gauss’s law states that the net electric flux through a closed surface is equal to the total charge enclosed by the surface divided by the permittivity of free space.
  • Use the method of images to solve problems involving conductors and dielectrics. The method of images involves placing imaginary charges in the problem in such a way that the boundary conditions are satisfied.
  • Use superposition to combine the effects of multiple charges. The principle of superposition states that the net electric field due to a collection of charges is the vector sum of the electric fields due to each individual charge.
  • Use energy conservation to solve problems involving the motion of charged particles. Energy conservation can be used to determine the velocity and trajectory of charged particles in electric fields.

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