پچھلے سال NEET سوال - Lcr سرکٹ ایپلی کیشنز

  • سوال۔ 220 V، 50 Hz کا ایک متبادل وولٹیج 2µF کیپسیٹینس کے ایک کیپسیٹر پر لگایا جاتا ہے۔ اس میں بہنے والے کرنٹ کی rms قدر کا حساب لگائیں۔ (NEET 2015)
The answer is 11 mA.

The formula for the rms value of current through a capacitor is: I_rms = V_rms / X_C

Irms = (Vrms) / (Xc)


In this case, we have:

Vrms = 220 V C = 2µF = 2 * 10^-6 F


So, the rms value of current is:

Irms = (220 V * √2) / (2 * 10^-6 F) = 11 mA



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