Biomolecules and Chemistry in Everyday Life - Result Question 31

32. The substituents $R _1$ and $R _2$ for nine peptides are listed in the table given below. How many of these peptides are positively charged at $pH=7.0$ ?

(2012)

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Peptide $R_1$ $R_2$
$I$ $H$ $H$
$II$ $H$ $CH_3$
$III$ $CH_2COOH$ $H$
$IV$ $CH_2CONH_2$ $(CH_2)_4NH_2$
$V$ $CH_2CONH_2$ $CH_2CONH_2$
$VI$ $(CH_2)_4NH_2$ $(CH_2)_4NH_2$
$VII$ $CH_2COOH$ $CH_2COMH_2$
$VIII$ $CH_2 OH$ $(CH_2)_4NH_2$
$IX$ $(CH_2)_4NH_2$ $CH_3$
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Answer:

Correct Answer: 32. $(4)$

Solution:

  1. The amino acid remain completely in Zwitter ionic form at its isoelectric point. Amino acids with additional acidic group have their isoelectric $pH$ less than $7.0$ and increasing $pH$ above isoelectric point makes them anionic.

On the other hand, amino acids with additional basic group have their isoelectric $pH$ greater than $7.0$ and decreasing $pH$ below isoelectric point (by adding acid solution) makes them cationic. The given peptide with followings $R _1$ and $R _2$ are basic, will remain protonated (cationic) at $pH=7.0$.

Peptide $\boldsymbol{R} _{\mathbf{1}}$ $\boldsymbol{R} _{\mathbf{2}}$
$IV$ $CH _2 CONH _2$ $\left(CH _2\right) _4 NH _4$
$VI$ $\left(CH _2\right) _4 NH _2$ $\left(CH _2\right) _4 NH _4$
$VIII$ $CH _2 OH$ $\left(CH _2\right) _4 NH _4$
$IX$ $\left(CH _2\right) _4 NH _2$ $CH _3$

Thus, $4$ is the correct integer.