Coordination Compounds 1 Question 10
10. The number of geometric isomers that can exist for square planar $\left[Pt(Cl)(py)\left(NH _3\right)\left(NH _2 OH\right)\right]^{+}$is (py = pyridine).
(a) $2$
(b) $3$
(c) $4$
(d) $6$
(2015 Main)
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Answer:
Correct Answer: 10. (b)
Solution:
- $\left[Pt(Cl)(py)\left(NH _3\right)\left(NH _2 OH\right)\right]^{+}$is square planar complex. The structures are formed by fixing a group and then arranging all the groups.
Hence, this complex shows three geometrical isomers.
BETA
