Coordination Compounds 2 Question 10

11. The magnetic moment of an octahedral homoleptic $Mn(II)$ complex is $5.9$ BM. The suitable ligand for this complex is

(a) $CN^{-}$

(b) ethylenediamine

(c) $NCS^{-}$

(d) $CO$

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Answer:

Correct Answer: 11. (c)

Solution:

  1. The magnetic moment of the magnitude $5.9$ BM suggest the presence of $5$ unpaired electrons in $Mn(II)$. This can be cross verified by putting the value $(5)$ of unpaired electrons in the formula, $\mu=\sqrt{n(n+2)}$ BM

Thus, the valence electronic configuration of $Mn(II)$ in the complex is

<img src=“https://temp-public-img-folder.s3.amazonaws.com/sathee.prutor.images/sathee_image/cropped_2024_01_16_b4fdca9f34924034e8d8g-264_jpg_height_95_width_672_top_left_y_618_top_left_x_1300.jpg"width="420">

The octahedral homoleptic complex suggests $s p^{3} d^{2}$-hybridisation in the complex, i.e.

<img src=“https://temp-public-img-folder.s3.amazonaws.com/sathee.prutor.images/sathee_image/cropped_2024_01_16_b4fdca9f34924034e8d8g-264_jpg_height_135_width_694_top_left_y_811_top_left_x_1283.jpg"width="420">

Thus, $5$ unpaired electrons are present in the complex which suggest the presence of a weak ligand like $NCS^{-}$.