Coordination Compounds 2 Question 34
36. The spin only magnetic moment value (in Bohr magneton units) of $Cr(CO) _6$ is
(a) $0$
(b) $2.84$
(c) $4.90$
(d) $5.92$
(2009)
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Answer:
Correct Answer: 36. (a)
Solution:
- In $\operatorname{Cr}(CO) _6: 3 d^{6}$, has no unpaired electrons, zero magnetic moment.