Coordination Compounds 2 Question 40
42. The compound having tetrahedral geometry is
(a) $\left[Ni(CN) _4\right]^{2-}$
(b) $\left[Pd(CN) _4\right]^{2-}$
(c) $\left[PdCl _4\right]^{2-}$
(d) $\left[NiCl _4\right]^{2-}$
$(2004,1 M)$
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Answer:
Correct Answer: 42. (d)
Solution:
- $\underset{\text{Tetrahedral}}{\left[NiCl _4\right]^{2-}}: Ni^{2+}\left(3 d^{8}\right)$
In all other complexes, hybridisation at central metal is $d s p^{2}$ and complexes have square planar geometries.
BETA
