Hydrocarbons - Result Question 1
1. Consider the following reactions,
$A$ is
(2019 Main, 12 April II)
(a) $\mathrm{CH} \equiv \mathrm{CH}$
(b) $\mathrm{CH}_3-\mathrm{C} \equiv \mathrm{C}-\mathrm{CH}_3$
(c) $\mathrm{CH}_3-\mathrm{C} \equiv \mathrm{CH}$
(d) $\mathrm{CH}_2=\mathrm{CH}_2$
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Answer:
Correct Answer: 1. (c)
Solution:
- According to the given conditions, the compound should be alkyne with triple bond present at the terminal. The chemical reactions involved are as follows:
Step 1
Step 2
In step-1, prop-1-yne reacts with $\mathrm{Ag}_2 \mathrm{O}$ to form $\mathrm{CH}_3-\mathrm{C} \equiv \mathrm{C}-\mathrm{Ag}$, that forms white precipitates.
In step 2, prop-1-yne in presence of mercuric sulphate and dil $\cdot \mathrm{H}_2 \mathrm{SO}_4$ produces carbonyl compound $\left(\mathrm{CH}_3\right)_2 \mathrm{C}=\mathrm{O}$ which produces $\left(\mathrm{CH}_3\right)_2 \mathrm{CH}-\mathrm{OH}$ in presence of $\mathrm{NaBH}_4 \cdot 2^{\circ}$ alcohol on reaction with Lucas reagent produces turbidity in about $5$ min .
BETA
