Hydrocarbons - Result Question 13
13. The highest boiling point is expected for
(1986,1 M)
(a) iso-butane
(b) $n$-octane
(c) $2, 2, 3, 3$-tetramethyl butane
(d) $n$-butane
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Answer:
Correct Answer: 13. (b)
Solution:
- Boiling point of alkane increases with molar mass. Among isomeric alkanes, branching decreases boiling point. Therefore, $n$-octane has highest boiling point, higher than $2, 2, 3, 3$-tetramethyl-butane (an isomer of $n$-octane).
BETA
