Hydrocarbons - Result Question 40
23. The reaction of propene with $HOCl$ proceeds via the addition of
(2001)
(a) $H^{+}$ in the first step
(c) $OH^{-}$ in the first step
(b) $Cl^{+}$ in the first step
(d) $Cl^{+}$ and $OH^{-}$ single step
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Answer:
Correct Answer: 23. (b)
Solution:
- $HOCl \longrightarrow HO^{-}+Cl^{+}$
i.e. reaction is initiated by $Cl^{+}$(chloronium ion electrophile)
BETA
