Hydrocarbons - Result Question 83
71. When gas $A$ is passed through dry $KOH$ at low temperature, a deep red coloured compound $B$ and a gas $C$ are obtained. The gas $A$, on reaction with but-$2$-ene, followed by treatment with $Zn / H _2 O$ yields acetaldehyde. Identify $A, B$ and $C$.
(1994, 3 M)
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Solution:
- $CH _3-CH=CH-CH _3 \xrightarrow[Zn-H _2 O]{Gas A} 2 CH _3-CHO$
$\therefore$ Gas $A$ is ozone $\left(O _3\right)$
Also; Gas $A+KOH$ (dry) $\longrightarrow \underset{\text { deep red coloured }}{B}+$ Gas $C$
$\therefore 4 O _3+4 KOH \longrightarrow \underset{B}{4 KO_3}+{2 H_2 O}+\underset{C}{O_2}$
BETA
