Organic Chemistry Basics Result Question 20

20. In allene $\left(\mathrm{C} _3 \mathrm{H} _4\right)$, the type(s) of hybridisation of the carbon atoms, is (are)

(2012)

(a) $s p$ and $s p^3$

(b) $s p$ and $s p^2$

(c) only $s p^3$

(d) $s p^2$ and $s p^3$

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Answer:

Correct Answer: 20. ( b )

Solution:

  1. Allene is the name given to propdiene, $\mathrm{H} _2 \mathrm{C}$ C $\mathrm{CH} _2$.

Hybridisation of an atom is determined by determining the number of hybrid orbitals at that atom which is equal to the number of sigma $(\sigma)$ bonds plus number of lone pairs at the concerned atom. $\operatorname{Pi}(\pi)$ bonds are not formed by hybrid orbitals, therefore, not counted for hybridisation.

Here, the terminal carbons have only three sigma bonds associated with them, therefore, hybridisation of terminal carbons is $s p^3$. The central carbon has only two sigma bonds associated, hence hybridisation at central carbon is $s p$.