Qualitative Analysis - Result Question 34
Passage
An aqueous solution of metal ion $M_1$ reacts separately with reagents $Q$ and $R$ in excess to give tetrahedral and square planar complexes, respectively. An aqueous solution of another metal ion $M_2$ always forms tetrahedral complexes with these reagents. Aqueous solution of $M_2$ on reaction with reagent $S$ gives white precipitate which dissolves in excess of $S$. The reactions are summarised in the scheme given below
35. Reagent $S$ is
(a) $K _4\left[Fe(CN) _6\right]$
(b) $Na _2 HPO _4$
(c) $K _2 CrO _4$
(d) $KOH$
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Answer:
Correct Answer: 35. $(d)$
Solution:
$Zn^{2+}$ on treatment with excess of $KOH$ produces $\left[Zn(OH) _4\right]^{2-}$.