Qualitative Analysis - Result Question 34

Passage

An aqueous solution of metal ion $M_1$ reacts separately with reagents $Q$ and $R$ in excess to give tetrahedral and square planar complexes, respectively. An aqueous solution of another metal ion $M_2$ always forms tetrahedral complexes with these reagents. Aqueous solution of $M_2$ on reaction with reagent $S$ gives white precipitate which dissolves in excess of $S$. The reactions are summarised in the scheme given below

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35. Reagent $S$ is

(a) $K _4\left[Fe(CN) _6\right]$

(b) $Na _2 HPO _4$

(c) $K _2 CrO _4$

(d) $KOH$

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Answer:

Correct Answer: 35. $(d)$

Solution:

$Zn^{2+}$ on treatment with excess of $KOH$ produces $\left[Zn(OH) _4\right]^{2-}$.



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