sblock Elements 1 Question 26
26. In which of the following reactions $\mathrm{H}_2 \mathrm{O}_2$ acts as a reducing agent?
(2014 Main)
I. $\mathrm{H}_2 \mathrm{O}_2+2 \mathrm{H}^{+}+2 e^{-} \longrightarrow 2 \mathrm{H}_2 \mathrm{O}$
II. $\mathrm{H}_2 \mathrm{O}_2-2 e^{-} \longrightarrow \mathrm{O}_2+2 \mathrm{H}^{+}$
III. $\mathrm{H}_2 \mathrm{O}_2+2 e^{-} \longrightarrow 2 \mathrm{OH}^{-}$
IV. $\mathrm{H}_2 \mathrm{O}_2+2 \mathrm{OH}^{-}-2 e^{-} \longrightarrow \mathrm{O}_2+2 \mathrm{H}_2 \mathrm{O}$
(a) I and II
(b) III and IV
(c) I and III
(d) II and IV
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Answer:
Correct Answer: 26. (d)
Solution: Release of electron is known as reduction. So, $\mathrm{H}_2 \mathrm{O}_2$ acts as reducing agent when it releases electrons.
Here, in reaction (II) and (IV), $\mathrm{H}_2 \mathrm{O}_2$ releases two electron, hence reaction (II) and (IV) is known as reduction.
In reaction (I) and (III), two electrons are being added, so (I) and (III) represents oxidation.
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