sblock Elements - Result Question 67
20. $MgCl_2 \cdot 6 H_2 O$ on heating gives anhydrous $MgCl_2$.
$(1982,1 M)$
Subjective Questions
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Answer:
Correct Answer: 20. $F$
Solution:
- $\mathbf{M g}$ can form basic carbonate while $\mathbf{M n}$ cannot.
$5 Mg^{2+}+6 CO_3^{2-}+7 H_2 O \longrightarrow 4 MgCO_3 \cdot Mg(OH)_2$
$$ · 5 H_2O + 2 HCO_3^{-} $$
BETA
