Transition and InnerTransition Elements - Result Question 37
37. The reaction which proceed in the forward direction is
(1991, 1M)
(a) $\mathrm{Fe}_2 \mathrm{O}_3+6 \mathrm{HCl} \longrightarrow 2 \mathrm{FeCl}_3+3 \mathrm{H}_2 \mathrm{O}$
(b) $\mathrm{NH}_3+\mathrm{H}_2 \mathrm{O}+\mathrm{NaCl} \longrightarrow \mathrm{NH}_4 \mathrm{Cl}+\mathrm{NaOH}$
(c) $\mathrm{SnCl}_4+\mathrm{Hg}_2 \mathrm{Cl}_2 \longrightarrow \mathrm{SnCl}_2+2 \mathrm{HgCl}_2$
(d) $2 \mathrm{CuI}+\mathrm{I}_2+4 \mathrm{H}^{+} \longrightarrow 2 \mathrm{Cu}^{2+}+4 \mathrm{KI}$
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Answer:
Correct Answer: 37. (a)
Solution: $\mathrm{Fe}_2 \mathrm{O}_3$ is a basic oxide, neutralised by HCl spontaneously forming $\mathrm{FeCl}_3$ and water.
BETA
